Can someone help me with this question asap lol
2 answers:
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(4x - 3)(2x - 1) ≥ 0
First, find the zeros:
4x - 3 = 0 2x - 1 = 0
x = x =
Next, plot these points and choose test points on the outside and between the zeros:
←-------0------------
------
------1------→
Lastly, plug in the test points and look for a positive result (since it is greater than 0).
Test Point 0: [4(0) - 3][2(0) - 1] = ( - )( - ) = + THIS WORKS!
Test Point : [4(
) - 3][2(
) - 1] = ( - )( + ) = - <em>This does NOT work</em>
Test Point 1: [4(1) - 3][2(1) - 1] = ( + )( + ) = + THIS WORKS!
Answer: x ≤ or x ≥
Interval Notation: (-∞, ] U [
, ∞)
Graph: ←------
--------→