Answer:
1. Consistent equations
x + y = 3
x + 2·y = 5
2. Dependent equations
3·x + 2·y = 6
6·x + 4·y = 12
3. Equivalent equations
9·x - 12·y = 6
3·x - 4·y = 2
4. Inconsistent equations
x + 2 = 4 and x + 2 = 6
5. Independent equations
y = -8·x + 4
8·x + 4·y = 0
6. No solution
4 = 2
7. One solution
3·x + 5 = 11
x = 2
Step-by-step explanation:
1. Consistent equations
A consistent equation is one that has a solution, that is there exist a complete set of solution of the unknown values that resolves all the equations in the system.
x + y = 3
x + 2·y = 5
2. Dependent equations
A dependent system of equations consist of the equation of a line presented in two alternate forms, leading to the existence of an infinite number of solutions.
3·x + 2·y = 6
6·x + 4·y = 12
3. Equivalent equations
These are equations with the same roots or solution
e.g. 9·x - 12·y = 6
3·x - 4·y = 2
4. Inconsistent equations
Inconsistent equations are equations that are not solvable based on the provided set of values in the equations
e.g. x + 2 = 4 and x + 2 = 6
5. Independent equations
An independent equation is an equation within a system of equation, that is not derivable based on the other equations
y = -8·x + 4
8·x + 4·y = 0
6. No solution
No solution indicates that the solution is not in existence
Example, 4 = 2
7. One solution
This is an equation that has exactly one solution
Example 3·x + 5 = 11
x = 2
You have to go through your x-axis and up or down you y-axis and then determine if the end point are on the right plot form
Answer:
1/9
Step-by-step explanation:
For these questions, you have to first find the probability of each event individually occuring then multiply these two probabilities together. So, lets first find the probability of Event 1 occuring (rolling a number higher than 1). On a dice, we know that there are 6 numbers (1, 2, 3, 4, 5, 6) of which the numbers 5 and 6 are higher than 4. Therefore, the proability of Event 1 occuring is 2/6 = 1/3. Now, we find the probability of event 2 occuring.
We know that there are 3 options on the spinner that the arrow can land on. It is also evident that they all have the same chance of landing on it. Therefore, the possibility is 1/3.
Now that we have both of our probabilities, we multiply the answer together.
Therefore, our answer will be:
1/3 x 1/3, which gives 1/9.
Answer:
a^14b^12
Step-by-step explanation:
okay so lets distribute the 2
so you get -a^6b^10 and a^8b^2
add
Answer:
y
=
3
2
x
+
1
Explanation:
To find the slope
(
m
)
of the straight line that passes through two points
(
x
1
,
y
1
)
and
(
x
2
,
y
2
)
apply:
(
y
1
−
y
2
)
=
m
(
x
1
−
x
2
)
In this example our two points are
(
0
,
1
)
and
(
2
,
4
)
Hence:
(
1
−
4
)
=
m
(
0
−
2
)
−
3
=
−
2
m
→
m
=
3
2
The equation of a straight line in slope
(
m
)
and intercept
(
c
)
form is:
y
=
m
x
+
c
In this example:
y
=
3
2
x
+
c
Since the point
(
0
,
1
)
is on this line
→
1
=
0
+
c
Hence,
c
=
1
∴
y
=
3
2
x
+
1
is our required straight line.
Step-by-step explanation:
