Answer:
Step-by-step explanation:
<u>The rule for this dilation is:</u>
<u>Apply this rule to point B(4, 6):</u>
A. 3272.4
b.349.92
c. 198.432
d. 194.688
Given:
Composite figure.
The figure splitted into two shapes.
One is vertical cuboid and other is horizontal cuboid
To find:
Total surface area of the figure
Solution:
<u>Vertical cuboid:</u>
Length = 14 inches
Width = 12 inches
Height = 24 inches
Surface area = 2(lw + wh + lh)
= 2(14 × 12 + 12 × 24 + 14 × 24)
= 2(168 + 288 + 336)
Surface area = 1584 square inches
<u>Horizontal cuboid:</u>
Length = 14 inches
Width = 10 inches
Height = 30 - 12 = 18 inches
Surface area = 2(lw + wh + lh)
= 2(14 × 10 + 10 × 18 + 14 × 18)
= 2(140 + 180 + 252)
Surface area = 1144 square inches
Total surface area = 1584 + 1144
= 2728 square inches
The total surface area of the figure is 2728 square inches.
Answer:
630.
Step-by-step explanation:
<u>Given the following data;</u>
Dimensions for cube = ¼ inches
Volume = 1/64 cubic inches.
For rectangular box;
Length = 2½ = 5/2 inches.
Width = 2¼ = 9/4 inches.
Height = 1¾ = 7/4 inches.
Volume = 315/32 inches
Therefore, to find the amount of cubes;
Substituting into the equation, we have;
Number of cubes = 630
15 + 2x - 4 = 9x + 11 - 7x
2x + 11 = 2x + 11
always true
2x + 3(4x - 1) = 2(5x + 3) + 4x
2x + 12x - 3 = 10x + 6 + 4x
14x - 3 = 14x + 6
never true