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Anna11 [10]
3 years ago
15

Why does my inbox keep getting notifications and then disappearing?

Computers and Technology
2 answers:
Gala2k [10]3 years ago
8 0

Answer:

someone is tryna message you but they got rid of privite messages.

ikr! its trippin ><

                      ---

Explanation:

ArbitrLikvidat [17]3 years ago
6 0

Answer:

ikr me 2?!!

Explanation:

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ipn [44]

the opening tag for an HTML document

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3 years ago
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(Business: check ISBN-10) An ISBN-10 (International Standard Book Number) consists of 10 digits: d1d2d3d4d5d6d7d8d9d10. The last
Aneli [31]

Answer:

 The solution code is written in Python 3

  1. digits = input("Enter 9 digits: ")
  2. multiplier = 1
  3. total = 0
  4. for x in digits:
  5.    total += int(x) * multiplier  
  6.    multiplier += 1
  7. checksum = total % 11  
  8. if(checksum == 10):
  9.    print(digits + "X")
  10. else:
  11.    print(digits + str(checksum))

Explanation:

Firstly, use input function to get user input for 9 digits (Line 1)

Next we can use a for-loop to estimate the summation (d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5+ d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9) ( Line 6-8)

Then only apply % operator to get the remainder of total and get the checksum (Line 10)

Next create if and else statement to print the digits string joined with X if checksum is 10 else join digits string with checksum value (Line 12 -15)

7 0
3 years ago
Assign decoded_tweet with user_tweet, replacing any occurrence of 'TTYL' with 'talk to you later'. Sample output with input: 'Go
nekit [7.7K]

Answer:

I am going to use the Python programming language to answer this. The source code is given below:

print("Enter your tweet here")

user_tweet = input()

decoded_tweet = user_tweet.replace('TTYL', 'talk to you later')

print("This is the decoded tweet: ")

print(decoded_tweet)

Explanation:

In the program the replace() module was used to replace 'TTYL' with 'talk to you later.'

Attached is the screenshot of the output.

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3 years ago
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Array Challenge Have the function ArrayChallenge (arr) take the array of numbers stored in arr and return the string true if any
vampirchik [111]

Answer:

The code is given as follows,

Explanation:

Code:

#include <stdio.h>

#include <string.h>  

int n; //to store size of array  

char* ArrayChallenge(int arr[]) //function returns string true or false

{

  int i, j;

  int sum = 0;

  for(i = 0; i < n; i++)

  {

      sum = sum + arr[i]; //count sum

  }  

  for(i = 0; i < n; i++)

  {

      for(j = i+1; j < n; j++) //loop for every two elements in array

      {

          if(arr[i]*arr[j] > 2*sum) //check if proudct of two elements > 2 times sum

          {

              printf("\n%d x %d = %d, 2xSum = %d\n", arr[i], arr[j], arr[i]*arr[j], 2*sum);

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          }

      }

  }

  return "false"; // If proudct of two elements < 2 times sum. return false

}  

int main()

{  

  printf("\nEnter size of array: ");

  scanf("%d", &n); //read size of array

  int A[n]; //array of size n

  printf("\nEnter array elements: ");

  int i;

  for(i = 0; i < n; i++)

  {

      scanf("%d", &A[i]); //read array from stdin

  }

  printf("%s\n",ArrayChallenge(A)); //ccall function and print answer

 

  return 0;

}

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