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sdas [7]
4 years ago
7

If the difference between the measures of the two smaller angles of a right triangle is 20 degrees what is the measure, in degre

es, of the smallest angle?
Mathematics
2 answers:
nordsb [41]4 years ago
8 0

Answer:

Measure of the smallest angle = 35 degrees.

Step-by-step explanation:

As it is a right triangle the values of the 2 smaller angles will add up to 90 degrees.

So  the 2 angles can be written as x and 90-x and  we have:

(90 - x) - x = 20

-2x = 20 - 90 = -70

x = 35.

So the 2 angles are 35 and 55 degrees.

xz_007 [3.2K]4 years ago
3 0

Answer:The  measure of the smallest angle is 35 degrees.

Step-by-step explanation:

a  + b = 90

a-b = 20

2a = 110

a = 55

90 -55= 35

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3 years ago
How many kilograms of sugar will you recieve if you spend 25.00 pounds and the sugar costs you 5.00 pounds per 15kg?
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4 0
3 years ago
Each letter of the word "thunderstorm" has been written on a separate slip of paper and put into a box. Find the probability of
xxTIMURxx [149]

SOLUTION

From the question, we want to find the probability of selecting a slip of paper with the letter t on it, then selecting the letter r, with replacement.

This means the probability of selecting t and r.

That is

P(t)\times P(r)

There are 12 letters (total outcomes). And there are 2r and 2t.

So probability becomes

\begin{gathered} \frac{possible\text{ outcome}}{\text{total outcome }} \\ P(t)=\frac{2}{12} \\ P(r)=\frac{2}{12} \\ P(t)\times P(r)=\frac{2}{12}\times\frac{2}{12} \\ =\frac{1}{6}\times\frac{1}{6} \\ =\frac{1}{36} \end{gathered}

Hence the answer is

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7 0
1 year ago
Divide.<br> (4x4 - 4x2 – x-3) = (2x2 – 3)
inn [45]

Given:

Division problem:

(4x^4-4x^2-x-3)\div (2x^2-3)

To find:

The solution for the given division problem.

Solution:

We have,

(4x^4-4x^2-x-3)\div (2x^2-3)

Here, 4x^4-4x^2-x-3 is the dividend and (2x^2-3) is divisor.

Using the long division method we get

\underline{2x^2-3}|\overline{4x^4-4x^2-x-3}|\underline{2x^2+1}

            \underline{4x^4-6x^2}

                      2x^2-x-3                      (After subtraction)

                      \underline{2x^2\quad \quad  -3}

                          \underline{\quad -x\quad}                        (After subtraction)

Now,

\dfrac{4x^4-4x^2-x-3}{2x^2-3}=2x^2+1-\dfrac{x}{2x^2-3}

Therefore, the required solution is 2x^2+1-\dfrac{x}{2x^2-3}.

5 0
3 years ago
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