1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sdas [7]
4 years ago
7

If the difference between the measures of the two smaller angles of a right triangle is 20 degrees what is the measure, in degre

es, of the smallest angle?
Mathematics
2 answers:
nordsb [41]4 years ago
8 0

Answer:

Measure of the smallest angle = 35 degrees.

Step-by-step explanation:

As it is a right triangle the values of the 2 smaller angles will add up to 90 degrees.

So  the 2 angles can be written as x and 90-x and  we have:

(90 - x) - x = 20

-2x = 20 - 90 = -70

x = 35.

So the 2 angles are 35 and 55 degrees.

xz_007 [3.2K]4 years ago
3 0

Answer:The  measure of the smallest angle is 35 degrees.

Step-by-step explanation:

a  + b = 90

a-b = 20

2a = 110

a = 55

90 -55= 35

You might be interested in
Help with 8 please I need help
Dimas [21]
You multiply the amount of mix by 3 and you milk by 3 as well...
8 0
3 years ago
the force needed to break a board varies inversely with its length. If tom uses 20lb of pressure to break a 1.5 -ft board, how m
jasenka [17]

\qquad \qquad \textit{inverse proportional variation} \\\\ \textit{\underline{y} varies inversely with \underline{x}} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}}{x}~\hfill } \\\\ \textit{\underline{x} varies inversely with }\underline{z^5} ~\hspace{5.5em} \stackrel{\textit{constant of variation}}{x=\cfrac{\stackrel{\downarrow }{k}}{z^5}~\hfill } \\\\[-0.35em] ~\dotfill

\stackrel{\textit{"f" varies inversely with "L"}}{f=\cfrac{k}{L}}\qquad \textit{we also know that} \begin{cases} f=\stackrel{lbs}{20}\\ L=\stackrel{ft}{1.5} \end{cases} \\\\\\ 20=\cfrac{k}{1.5}\implies 30=k~\hfill \boxed{f=\cfrac{30}{L}} \\\\\\ \textit{when L = 6, what is "f"?}\qquad f=\cfrac{30}{6}\implies f=5

3 0
3 years ago
a factory could produce 84 toy robots in one day. They purchased some new equipment. Now they can produce 105 robots in one day.
kompoz [17]

Answer:

The answer to the question is

25 % increase in production rate

Step-by-step explanation:

To solve the question, we note that

Initial number of products = 84 toy robots per day

Present production rate = 105 robots per day

The percentage increase is given by the increase in production rate divided by the original production rate multiplied by 100  

Where increase in production rate = 105 - 84 = 21

Percentage increase = 21/84 ×100 = 25 % increase

3 0
3 years ago
If 4 (log3 1/27)=X what is the value of X
givi [52]
4(log _{3} 1/27) =x
log _{3}  \frac{1}{27}^4  =x

Now remember: b^y=x  \\ equals  \\ log _{b}x=y

3^x =  \frac{1}{27}^4
3^x =  \frac{1}{531441}
log _{3} \frac{1}{531441} =x
\frac{ln\frac{1}{531441}}{ln3} = x
\frac{1}{531441} = 0.000002
you can now enter this into your calculator...

Answer: x = -0.083


7 0
3 years ago
Read 2 more answers
A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
Aleks [24]

Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

Let the percentage of the components bought from supplier C that are faulty = y%

y% × 6% of x = 0.0528x

y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

y% = 0.88 = 88%

The percentage of the components bought from supplier C that are faulty = 88%

3 0
4 years ago
Other questions:
  • I need desperate help
    5·1 answer
  • (2a-b)^5 what is the answer to this problem
    9·1 answer
  • Who was the first person to do a math equation?....​
    5·2 answers
  • For a particular population, the annual rate of growth is 8.5%.
    14·2 answers
  • Solve eqaution 15m+22=-7m+18
    12·2 answers
  • The Martin family’s truck gets an average of 20 miles per gallon.Predict his many miles they can drive using 5 gallons of gas
    9·1 answer
  • A swimmer dove below the surface of the ocean. After 2 minutes, she was 12 meters below the surface. At what rate was she diving
    11·1 answer
  • a rectangles side lengths are 8 cm and 4 cm. Approximate the length of the diagonal of the rectangle to the nearest tenth.
    10·1 answer
  • How many times does 94 go into 376?
    10·1 answer
  • How do you find the x and y intercept with just the slope(y=mx+b)
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!