The margin of error is defined as

where
σ = population standard deviation
n = sample size
z* = aconstant that depends on the confidence level.
At the 95% confidence level, z* = 1.96.
The confidence interval is calculated as
(μ - E, μ + E)
Given:
μ = 3, the mean number of pets,
E = 2.5, margin of error at the 95% confidence level.
Therefore the 95% confidence interval is
(3 - 2.5, 3 +2.5) = (0.5, 5.5)
Because we can only count whole numbers of pets, the confidence interval is (0, 5).
Answer:
At the 95% confidence level, the 5th graders own between 0 and 5 pets.
Greater than, the highest amount you can get by multiplying 1/2 and a number lower than it, is 1.
Answer:
To check all the events (6), we label the chips. Suppose one chip with 1 is labeled R1 and the other B1 (as if they were red and blue). Now, lets take all combinations; for the first chip, we have 4 choices and for the 2nd chip we have 3 remaining choices. Thus there are 12 combinations. Since we dont care about the order, there are only 6 combinations since for example R1, 3 is the same as 3, R1 for us.
The combinations are: (R1, B1), (R1, 3), (R1, 5), (B1, 3), (B1, 5), (3,5)
We have that in 1 out of the 6 events, Miguel wins 2$ and in five out of the 6 events, he loses one. The expected value of this bet is: 1/6*2+5/6*(-1)=-3/6=-0.5$. In general, the expected value of the bet is the sum of taking the probabilities of the outcome multiplied by the outcome; here, there is a 1/6 probability of getting the same 2 chips and so on. On average, Miguel loses half a dollar every time he plays.
please mark me brainliest :)
Answer:
20 x 4 = 60
Step-by-step explanation:
because it's says how many