Please help the following questions
1 answer:
Answer:
<em>Option D</em>
Step-by-step explanation:
Assume that these polygons were similar. You could tell that if they were, ABCD ~ EFGH, and is already noted by the answer choices. We can conclude that AB ~ EF, CD ~ GH and so on. To prove that these shapes are similar, we must form a like proportionality among these side;
As the proportions we formed were to equal to one another,<em> the solution must be option D!</em>
You might be interested in
Answer:
Step-by-step explanation:
Initially the graph f (x) is shifted horizontally to the right.
When the graph shifts to right the function then becomes
f(x)→f(x-b)
Where b is the units by which it is shifted towards right .
So, in the figure we can see that it is shifted 2 units to the right .
So, f(x)→f(x-2)
Since f(x) is
So, f(x-2) =
Now the new obtained graph is again shifted vertically upward
When the graphs shifts upward f(x) →f(x)+b
where b is the units by which it is shifted upward
So, our obtained f(x-2) when shifted upward by 4 units so using the above given transformation of upward shift i.e. f(x) →f(x)+b
So, Our new graph h(x) = f(x-2)+4
⇒