Question

What is the length of segment AB with point A and B located at (-4, 1) and (2, 9)

Answer 1

Answer:

The length of segment AB is 10

Step-by-step explanation:

The distance formula is d=$\sqrt{ (x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}$

With the points (-4,1) and (2,9) you know that $-4=x_{1}, 2=x_{2}, 1=y_{1} ,9=y_{2}$

Now you put the numbers into the distance formula

d=$\sqrt{(2-(-4))^{2}+(9-1)^2$

(2-(-4) turns into (2+4) because two negatives equal a positive.

After adding and subtracting you get d=$\sqrt{6^2+8^2$

You then square $6^2$ and $8^2$ to get $\sqrt{36+64$

After adding 34+64 you get $\sqrt{100$, which is 10

So the length of segment AB is 10

Answer 2

Answer:

The answer is 10 units

Step-by-step explanation:

The distance between two points or a line segment can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} }$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-4, 1) and (2, 9)

The length of segment AB is

$|AB| = \sqrt{ ({ - 4 - 2})^{2} + ({1 - 9})^{2} } \\ = \sqrt{( { - 6})^{2} + ({ - 8})^{2} } \\ = \sqrt{36 + 64} \\ = \sqrt{100} \: \: \: \: \: \: \: \: \\ = 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

We have the final answer as

10 units

Hope this helps you