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3 years ago

-3x - 9y = 18 4x + 3y = 12

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

8 0

Answer: (6,-4)

X= 6 Y= -4

Step-by-step Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.

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4 years ago

Simplify the expression. Write the answer using scientific notation. (4 × 108)2

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2 years ago

Read 2 more answers

I need to be able to take a set of data, and find it's exponential function.

N76 [4]

Answer:

The process below should work.

Step-by-step explanation:

Let's pretend we have these two points we are trying to find an exponential equation for: (-2,6) and (2,1).

Exponential equations are of the form $y=a \cdot b^x$ where we must find $a$ and $b$ .

So you enter both points into that equation giving you:

$6=a \cdot b^{-2}$

$1=a \cdot b^{2}$

I'm going to divide equation 1 by 2 because if I do the a's will cancel and I could solve or b.

$\frac{6}{1}=\frac{a \cdot b^{-2}}{a \cdot b^2}$

$6=\frac{b^{-2}}{b^2}$

By law of exponent, I can rewrite the right hand side:

$6=b^{-2-2}$

$6=b^{-4}$

Now do ^(-1/4) on both sides to solve for b:

$6^\frac{-1}{4}=b$

Now we use one of the equations along with our value for b to find a:

$1=a \cdot b^2$ with $b=6^{\frac{-1}{4}}$

$1=a \cdot (6^{\frac{-1}{4}})^2$

Simplify using law of exponents:

$1=a \cdot 6^{-\frac{1}{2}}$

Multiply both sides by 6^(1/2) to solve for a:

$6^{\frac{1}{2}}=a$

$y=a \cdot b^x$ with $a=6^{\frac{1}{2}} \text{ and } b=6^{\frac{-1}{4}}$ is:

$y=6^\frac{1}{2} \cdot (6^{\frac{-1}{4})^x$

We can simplify a smidgen:

$y=6^\frac{1}{2} \cdot (6)^\frac{-x}{4}$

7 0

4 years ago