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leva [86]
3 years ago
6

The center is (0, 0), and a point on the circle is (1, 0).

Mathematics
1 answer:
Mila [183]3 years ago
6 0

Answer:

so it will be (1, 2)

Step-by-step explanation:

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Consider this product. x^2-4x-21/3x^3+6x x^2+8x/x^2+11x+24 Which values are excluded values for the product?
lesya [120]

Using the domain, it is found that x = -8 is excluded for the product.

The domain of a function is the <u>set that contains all possible input values</u>.

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In this problem, there are two fractions, and the points outside the domain, that is, the roots of the denominators, are excluded.

For the first fraction, they are:

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3x(x + 2) = 0

3x = 0 \rightarrow x = 0

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Hence, x = -2(not an option) is excluded.

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For the second fraction, the roots of the denominator are:

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Which is a quadratic equation with <u>coefficients</u> a = 1, b = 11, c = 24, hence:

\Delta = b^2 - 4ac = 11^2 - 4(1)(24) = 121 - 96 = 25

x_1 = \frac{-b - \sqrt{\Delta}}{2a} = \frac{-11 - 5}{2} = -8

x_2 = \frac{-b + \sqrt{\Delta}}{2a} = \frac{-11 + 5}{2} = -3

x = -3 can be factored with the numerator of the first fraction, so only x = -8 is excluded.

A similar problem is given at brainly.com/question/13136492

5 0
3 years ago
Need help on this answer
ziro4ka [17]
It is not correct because the second answer tells you how far to go up and down, not across.
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4 years ago
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ikadub [295]
1/3 divided by 4
1/3 divided by 4/1
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1/12 quarts are in each cup
8 0
3 years ago
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