Try this option:
1. for vertex (2;1) the first equation is: h=-b/2a, it means 2=-b/2a or b=-4a;
2. for vertex (2;1) the second equation is: ax²+bx+c=y, it means 1=4a+2b+c;
3. for point (6;7) the third equation is: ax²+bx+c=y, it means 7=36a+6b+c.
4. using three equation, it is possible to make up the system of equations (and solve it). Details are in the attached picture.
answer:
The graph is in the attachment.
Answer:
A -1/2
b 3/-4
C -1/-5
Step-by-step explanation:
Quadratic
y = ax^2 + bx + d
c (x) = ax^2 + bx + d
c (3) = a (3^2) + b (3) + d
c (3) = 9a + 3b + d = 15.50
c (7) = a (7^2 + b (7) + d
c (7) = 49a + 7b + d = 23.50
c (12) = a (12^2) + b (12) + d
c (12) = 144a + 12b + d = 56
solve using simultaneous equations... to get a b and d
use that to solve for x = 5
hope this helps?
Answer:
Step-by-step explanation:
Answer:
174
Step-by-step explanation: