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nignag [31]
2 years ago
5

Please help!!! I was sick when I got this for homework so I have no clue.

Biology
1 answer:
den301095 [7]2 years ago
6 0

Answer:

Number 3 is “dark”

Explanation:

After the Industrail Revolution, there was a large growth in dark peppered moth population.

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Calculate the number of amino acids encoded by a DNA sequence of 36 nucleotides
ipn [44]

Answer:

See answer below

Explanation:

Hi there,

Assuming this DNA strand is fully capable of being mature mRNA (5' m7G cap and PolyA tail), nucleotides lead to an mRNA codon, which is 3 nucleotides per codon. In turn, 1 codon leads to 1 amino acid. However, as a single strand, it must be capable of terminating translation, which always requires a stop codon, and thus 3 nucleotides. Hence, we must subtract this from the total amount of codons first.

Hence, only 11 amino acids will be coded by a single DNA strand 36 ncltd long.

thanks,

7 0
2 years ago
How does the cold spring graph differ from the normal weather graph?
MariettaO [177]
The Normal Graph has higher increments of increasing and decreasing; the Cold Spring howeverhas increases and decreases at small amounts, but an overall increase.
6 0
2 years ago
The planets show phases just like the moon does. Explain why we will never see a full Venus or full Mercury, even though we can
faltersainse [42]

Answer:

Because Venus and Mercury are closer to the sun they are never visible at around midnight

Explanation:

I've read about this in articles

6 0
3 years ago
A population is made up of individuals where 77 have the A1A1 genotype, 65 have the A1A2 genotype, and 123 have the A2A2 genotyp
lana [24]

Answer:

Frequency of allele A1- 0.41

Explanation:

In Hardy weinberg equilibrium,

P refers to the dominant allele

q refers to the recessive allele

The allele frequency will be p+q=1

The genotypic frequency is- P²+q²+2pq=1

P²= genotype of dominant trait ( A1A1)- 77

2pq= genotype of heterozygotes (2pq)- 65

q²= genotype of recessive trait (A2A2)-  123

Total number of offsprings= 77+  65+ 123

                                            = 265

Now to calculate allele frequency of A1=

\dfrac{\text{number of A1A1 offspring}}{ \text{total number of offspring}}+\dfrac{1}{2}(\dfrac{\text{number of A1A2 offspring}}{\text{total number of offspring}})

= 77/265 + 1/2( 65//265)

=  0.290+ 0.122

= 0.413

Thus, 0.41 is correct.

3 0
3 years ago
What is the term "basic unit of matter" refer to? A.Atoms.. B.Elements.. C.Molecules..
gizmo_the_mogwai [7]
I belive the answer is A
5 0
2 years ago
Read 2 more answers
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