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3 years ago

12

Write a polynomial function, p(x) with degree 3 that has p(7)=0

1 answer:

MArishka [77]3 years ago

4 0

Answer:

$p (x) = x^{3} - 21x^{2}+ 147x - 343$

is the required polynomial with degree 3 and p ( 7 ) = 0

Step-by-step explanation:

Given:

p ( 7 ) = 0

To Find:

p ( x ) = ?

Solution:

Given p ( 7 ) = 0 that means substituting 7 in the polynomial function will get the value of the polynomial as 0.

Therefore zero's of the polynomial is seven i.e 7

Degree : Highest raise to power in the polynomial is the degree of the polynomial

We have the identity,

$(a -b)^{3} = a^{3}-3a^{2}b +3ab^{2} - b^{3}$

Take a = x

b = 7

Substitute in the identity we get

$(x -7)^{3} = x^{3}-3x^{2}(7) +3x(7)^{2} - 7^{3}\\(x -7)^{3} = x^{3}-21x^{2} +147x - 343$

Which is the required Polynomial function in degree 3 and if we substitute 7 in the polynomial function will get the value of the polynomial function zero.

p ( 7 ) = 7³ - 21×7² + 147×7 - 7³

p ( 7 ) = 0

$p (x) = x^{3} - 21x^{2}+ 147x - 343$

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Suppose the population of a town is 134,000 in 2004. The population increases at a rate of 3 percent

ozzi

Answer:

start by getting 3% of 134000 and adding that on which gives us 138020 for the year 2005. get 3% of 138020 and add that on for the population in 2006 etc. in 2020 the population would be 215,031

Step-by-step explanation:

5 0

4 years ago

Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)

PtichkaEL [24]

Answer:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

Step-by-step explanation:

$(x^{3} x^{-6} )^{2}$ is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

$1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}$

Both the formula can be applied to the expression( $(x^{3} x^{-6} )^{2}$ ) during the first step while solving it.

<u>Applying formula (1):</u>

$(x^{3} x^{-6} )^{2}$

Comparing the terms of $(x^{3} x^{-6} )$ with $p^a \times p^b$

$p=x, a =3, b=-6$

$\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $(x^{-3} )^{2}$

<u>Applying formula (2):</u>

Comparing the terms of $(x^{3} x^{-6} )^{2}$ with $(p^a \times q^b)^c$

$p=q=x, a =3, b=-6, c=2$

$\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $x^6 x^{-12}$ .

So, the answers can be:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

8 0

3 years ago

A 943-foot tree has grown at a constant rate each year. In the equation below, t is the age of the three in years.

Mazyrski [523]

Answer:

B. 41 feet per year

Step-by-step explanation:

943/23= 41

Total feet / coefficient= feet per year

7 0

3 years ago

Read 2 more answers

Last weekend, Charlie raked leaves in his front yard l. He noticed that 7/3 kilograms of leaves filled 4/9 of a bag. What is the

Archy [21]

7kg:4/9 bag
?kg:1 bag

7÷4/9 or 7×9/4=63/4 or 15.75. As a result, the unit rate is 15.75 kg of leaves per bag. Hope it help!

3 0

3 years ago

in a game involving a pair of fair dice a player rolls the dice until he gets a sum of 7 let z equal the number of rolls it take

Anarel [89]

Answer:

z = 36 rolls , probability for getting 7 = 1/6

Step-by-step explanation:

A die has 6 possible outcomes, which sums to 36 for two dice for every value on both dice.

The outcomes for rolling both dice for 36 times gives 6 possible outcomes summing to 7, that is, (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1).

There the probability of getting a sum dice of 7 is:

= 6 / 36 = 1/6

8 0

3 years ago