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2 years ago

What's 8,736 divided by 51

2 answers:

8 0

The correct answer is 171.2.
8736 divided into 51 parts is 171.2.
The decimal could be extended infinitely. The highest I got was 171.2941176470588.

ohaa [14]2 years ago

8 0

The answer to your question is 171.

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Simplify 7 (2x + 4) + 14.

bearhunter [10]

Answer: 14x + 42

7(2x+4)+14

14x + 28 + 14

Step-by-step explanation:

6 0

3 years ago

1 of 5

Allisa [31]

Answer:

7/1296

Step-by-step explanation:

Multiply the two probabilities.

7/36 x 1/36 = 7/1296

3 0

2 years ago

Read 2 more answers

Please help me!!!!!!!

chubhunter [2.5K]

9514 1404 393

Answer:

y = -4x +2

Step-by-step explanation:

The equation you're writing is in slope-intercept form. The coefficient of x is the slope, which is the "rise"/"run" of the line.

Here, to get from the left point to the right point, you must go down 4 units (rise=-4) and 1 unit to the right (run=1). So, the slope is ...

m = rise/run = -4/1 = -4

The constant in the equation is the y-intercept: the y-coordinate of the point where the line crosses the y-axis. That point is marked as (0, 2), so its y-coordinate is 2.

The equation for the line is ...

y = -4x +2

8 0

2 years ago

The exchange rate of U.S. dollars to British pounds is .63. You have $4000 to convert to British pounds (£). How many British po

Reika [66]

Answer: £2520

Step-by-step explanation:

You have $4000 to convert to British pounds (?). 4,000*.63=2,520.

7 0

2 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

2 years ago