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3 years ago

A polygon with 12 sides is called a/an a. dodecagon. b. pentagon. c. undecagon.

Mathematics

2 answers:

mr_godi [17]3 years ago

6 0

The answer is dodecagon hopes this helps

Pepsi [2]3 years ago

5 0

The answer is A. dodecagon.

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See attachment, answer please.

Anton [14]

Answer:

4.5

Step-by-step explanation:

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3 years ago

A store offered a 15% discount for all employees. What is the amount of

Rom4ik [11]

Answer: discount amount is $6.75

Step-by-step explanation:

1. multiply 45 by 15% (0.15) = $6.75

2. price of an item with discounted amount would equal $38.25

4 0

2 years ago

I need an accurate answer please

kotykmax [81]

x = –6

Solution:

Given expression is $\sqrt[3]{x-2}+5=3$ .

Step 1: Isolate the radical by subtracting 5 from both sides of the equation.

$\Rightarrow\sqrt[3]{x-2}+5-5=3-5$

$\Rightarrow\sqrt[3]{x-2}=-2$

Step 2: Cube both sides of the equation to remove the cube root.

$\Rightarrow(\sqrt[3]{x-2})^3=(-2)^3$

Cube and cube root get canceled in left side of the equation.

$\Rightarrow\ x-2=-8$

Step 3: To solve for x.

Add 2 on both sides of the equation.

$\Rightarrow\ x-2+2=-8+2$

$\Rightarrow\ x=-6$

Hence the solution is x = –6.

6 0

3 years ago

When fishing off the shores of Florida, a spotted seatrout must be between 10 and 30 inches long before it can be kept; otherwis

Mademuasel [1]

Answer:

There is a 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

The lengths of the spotted seatrout that are caught, are normally distributed with a mean of 22 inches, and a standard deviation of 4 inches, so $\mu = 22, \sigma = 4$ .