Answer:
x= -2
y=0
z= 1
Step-by-step explanation:
{-x+5y-10z=-8
2x-y+10z=6}
{2x-y+10z=6
-7x-3y-10y=4}
{-x+5y-10z=-8
2x-y+10z=6} = x+4y=-2
{2x-y+10z=6
-7x-3y-10y=4} = -5x-4y=10
{x+4y=-2
-5x-4y=-10}. =. y= 0 x= -2
substitute x and y in -x+5y-10z=-8
-(-2)+5(0)-10z=-8
solve for z
z= 1
(x,y,z) = (-2,0,1)
hope this helps
The answer to this will be,
c. It will terminate.
Answer:
No
Step-by-step explanation:
Let's define our 2 terms first.
2x³y
2xy²
We see here that one term has a x³y and the other has a xy² term. Since they are not the same, the 2 terms are <em>not</em> like terms.
