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boyakko [2]
2 years ago
9

Need help

Mathematics
2 answers:
s344n2d4d5 [400]2 years ago
8 0
  • A rectangle garden is 50m long and 45 m broad. A path 2m wide is. running inside the garden.
  • Area of the rectangular garden = (50 × 45) square metres = 2250 square metres.
  • Area of the rectangle which is left after the path is paved = [(50-2×2)×(45-2×2)] square metres = [(50-4) × (45-4)] square metres = (46 × 41) square metres = 1886 square metres.
  • Therefore, the area of the path = (2250 - 1886) square metres = 364 square metres.
  • Therefore, the cost of gravelling the path at Rs. 40 per square metre = Rs. (40 × 364) = Rs. 14560.

<u>Answe</u><u>r</u><u>:</u>

<u>Rs.</u><u> </u><u>1</u><u>4</u><u>5</u><u>6</u><u>0</u>

Hope you could get an idea from here.

Doubt clarification - use comment section.

Sliva [168]2 years ago
4 0

In rectangle ABCD

  • L=50m
  • B=45m

\\ \sf{:}\longrightarrow Area=LB

\\ \sf{:}\longrightarrow Area=50(45)

\\ \sf{:}\longrightarrow Area=2250m^2

In rectangle PQRS

  • L=50-2=48m
  • B=45-2=43m

\\ \sf{:}\longrightarrow Area=LB

\\ \sf{:}\longrightarrow Area=48(43)

\\ \sf{:}\longrightarrow Area=2064m^2

Now

\\ \sf{:}\longrightarrow Area_{(Path)}=Area_{(ABCD)}-Area_{(PQRS)}

\\ \sf{:}\longrightarrow Area_{(Path)}=2250-2064=186m^2

Cost:-

\\ \sf{:}\longrightarrow 186(40)

\\ \sf{:}\longrightarrow Rs 7440

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