Question

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Answer 1

• A rectangle garden is 50m long and 45 m broad. A path 2m wide is. running inside the garden.
• Area of the rectangular garden = (50 × 45) square metres = 2250 square metres.
• Area of the rectangle which is left after the path is paved = [(50-2×2)×(45-2×2)] square metres = [(50-4) × (45-4)] square metres = (46 × 41) square metres = 1886 square metres.
• Therefore, the area of the path = (2250 - 1886) square metres = 364 square metres.
• Therefore, the cost of gravelling the path at Rs. 40 per square metre = Rs. (40 × 364) = Rs. 14560.

Answer:

Rs. 14560

Hope you could get an idea from here.

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Answer 2

In rectangle ABCD

• L=50m
• B=45m

$\\ \sf{:}\longrightarrow Area=LB$

$\\ \sf{:}\longrightarrow Area=50(45)$

$\\ \sf{:}\longrightarrow Area=2250m^2$

In rectangle PQRS

• L=50-2=48m
• B=45-2=43m

$\\ \sf{:}\longrightarrow Area=LB$

$\\ \sf{:}\longrightarrow Area=48(43)$

$\\ \sf{:}\longrightarrow Area=2064m^2$

Now

$\\ \sf{:}\longrightarrow Area_{(Path)}=Area_{(ABCD)}-Area_{(PQRS)}$

$\\ \sf{:}\longrightarrow Area_{(Path)}=2250-2064=186m^2$

Cost:-

$\\ \sf{:}\longrightarrow 186(40)$

$\\ \sf{:}\longrightarrow Rs 7440$