Hey there!
So, if
, this would mean that we would do
and from this, we would get 8.
We will then need to find what is
.
=
So, the equation would really look like
. . .
![\left[\begin{array}{ccc} 8*(7)-2*4 = 48 \\ \\ x=\boxed{7}\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%208%2A%287%29-2%2A4%20%3D%2048%20%5C%5C%20%5C%5C%20x%3D%5Cboxed%7B7%7D%5Cend%7Barray%7D%5Cright%5D%20)
Hope this helps.
~Jurgen
Answer:
The points are randomly scattered with no clear pattern
The number of points is equal to those in the scatterplot.
Step-by-step explanation:
The points in the residual plot of the line of best fit that is a good model for a scatterplot are randomly scattered with no clear pattern (like a line or a curve).
The number of points in the residual plot is always equal to those in the scatterplot.
It doesn't matter if there are about the same number of points above the x-axis as below it, in the residual plot.
The y-coordinates of the points are not the same as the points in the scatterplot.
Let Mary Sue have m necklaces and Betty have b necklaces.
And they have 603 necklaces altogether, that is
m + b =603
And Mary Sue has 115 more necklaces than Betty, that is
m=b +115
Substituting this value in first equation we will get
b+115+b=603
Subtracting 115
2b= 488
b= 244
So Betty have 244 necklaces .
980,507 i believe... maybe
Answer:
Let x = the charge in 1st city before taxes
Let y = the charge in 2nd city before taxes
Set up equation before taxes.
y = x - 1500 eq1
Set up equation for total tax paid.
0.065x + 0.06y = 378.75 eq2
Substitute eq1 into eq2.
0.065x + 0.06(x - 1500) = 378.75
0.065x + 0.06x - 90 = 378.75
0.125x - 90 = 378.75
0.125x = 468.75
x = 3750
Substitute this value of x into eq1.
y = 3750 - 1500
y = 2250
The hotel charge in city one is $3750 and the hotel charge in city two is $2250
