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Anna71 [15]
2 years ago
13

Choose the situation in which the use of exact numbers is most appropriate. A) Alice is adding peas to her vegetable soup B) Cas

ey is buying candy to hand out for Halloween C) Michael is baking cookies for a school fund-raiser D) Jenny is writing a check to cover her monthly car payment
Mathematics
2 answers:
likoan [24]2 years ago
5 0
D) Jenny is writing a check to cover her monthly car payment. 
zhenek [66]2 years ago
4 0
Hello!!

I believe your answer is D)
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Compare the values of the underlined digits?
amm1812
The value of 7 in 26,475 is ten times greater than the value of 7 in 503,497.

This is because the first 7 is in the tens place and the second seven is in the ones place. Everytime you move to the next "place" you are basically making the number ten times smaller or greater.
6 0
2 years ago
michael made 9/12 of his free throws at practice.what is 9/12 in simplest form i really don't get simplest form
ruslelena [56]
To get simplest form you make it the smallest fraction you can make it by dividing both sides by the same number until it's not possible anymore Hope that helped!
4 0
3 years ago
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Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
3 years ago
Felix wrote several equations and determined that only one of the equations has no solution. Which of these equations has no sol
lara [203]

Answer:

3(x-2)+x=4x+6

Step-by-step explanation:

case 1) we have

3(x-2)+x=4x-6

Solve for x

3x-6+x=4x-6

4x-6=4x-6

0=0 ----> is true for any value of x

therefore

The equation has infinite solutions

case 2) we have

3(x-2)+x=2x-6

3x-6+x=2x-6

4x-2x=-6+6

2x=0

x=0

case 3) we have

3(x-2)+x=3x-3

3x-6+x=3x-3

4x-3x=-3+6

x=3

case 4) we have

3(x-2)+x=4x+6

3x-6+x=4x+6

4x-4x=6+6

0=12 ------> is not true

therefore

The equation has no solution

4 0
2 years ago
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PLEASE HELP MEE!!!!! WILL GIVE BRAINLIEST AND HANGOUTS!!!!!!!!
jeka94

Answer:

Blue line: y = -2

Red line: y = 2/3 x + 2

Perpendicular to red line: y = -3/2x + 2

Parallel to red line: y = 2/3 x + any real number



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3 years ago
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