Answer:
0,∞
Thus, the range of the square root function is [0,∞)
Step-by-step explanation:
When its domain is greater than or equal to zero, its inverse is the squaring function. When its domain is all real numbers, its range includes complex numbers such as i, -1.
You want to make the denominator of the fractions to be equal to each other.
(2/n+8)+(4/n+1) multiply n+1 by n+8, and multiply n+8 by n+1
(4n+32/n^2+8)+(2n+2/n^2+8) Now that the denominators are equal we can solve the numinator by adding like terms.
4n+2n=6n, 32+2=34
Your final answer is 2(3n+17)/n^2+8
To solve this problem, we should set up an equation, letting x be the unknown number.
9 + x = 0
Next, we should subtract 9 from both sides to cancel out the +9 on the left side of the equation and get the variable alone.
x = -9.
Therefore, the number you are looking for is -9.
