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ludmilkaskok [199]
3 years ago
9

The inverse of the function f(x)=

" title=" \sqrt{x + 3} + 2" alt=" \sqrt{x + 3} + 2" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
irina [24]3 years ago
3 0

Answer:

f^-1 (x)=x^2-4x+1

Step-by-step explanation:

y=sqrt(x+3)+2

x=sqrt(y+3)+2

sqrt(y+3)=x-2

y+3=(x-2)^2

y+3=(x-2)(x-2)

y+3=x^2-2x-2x+4

y+3=x^2-4x+4

y=x^2-4x+4-3

y=x^2-4x+1

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