Answer:
The maximum power available to the motor is 2.4 MW
Step-by-step explanation:
The power of a circuit that has a current, I, and a voltage, V, is given by the relation
Electrical power, P = I²R = I× I×R = I × V
Therefore given that the parameters are;
Voltage in the d.c. power supply = 600 V d.c.
Maximum current in the motor = 4000 A
Therefore, we can find the power as follows;
Maximum motor power = Voltage × Current
The maximum motor power, P available = 600 V × 4000 A = 2400000 W which on converting to MW becomes;
The maximum power available to the motor , P = 2.4 MW.
