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3 years ago

PLEASE HELP!!!!!!!!!

Mathematics

1 answer:

STatiana [176]3 years ago

4 0

Answer:

answer is x=14.4.......,......

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6. On a bank account of $2,500, how much yearly interest will be paid if the rate is3.4%?

iVinArrow [24]

Multiply the amount in the account by the interest rate:

2500 x 0.034 = 85.00

Answer: $85.00

5 0

2 years ago

Math help!! This is really difficult

Reptile [31]

Answer:

y = -3/2 x +13

Step-by-step explanation:

We want our line to be perpendicular to

y = 2/3 x -1

The slope of this line is 2/3 (since it is written in the form y = mx+b and m is the slope)

Perpendicular lines have negative reciprocal slopes

m = -(3/2)

The slope of our new line is -3/2

We can use point slope form of the equation

y-y1 - m (x-x1)

y - 7 = -3/2 (x-4)

Distribute

y-7 = -3/2x +6

Add 7 to each side

y-7+7 = -3/2 x +6+7

y = -3/2 x +13

4 0

3 years ago

Does anyone know what 3.2 ÷ 0 ???

Assoli18 [71]

Answer:

Infinity

Step-by-step explanation:

Look it up, its how it works. 0 can go into 3.2 infinity times.

3 0

3 years ago

Please help.. will mark Brainliest!

hoa [83]

Answer:

Step-by-step explanation:

it is the same angle as angle one so it would be the same

6 0

3 years ago

Read 2 more answers

What is the solution to -x2 + 5x - 3

CaHeK987 [17]

The solution to the equation is $x=\frac{5-\sqrt{13}}{2}$ and $x=\frac{5+\sqrt{13}}{2}$

Explanation:

Given that the equation is $-x^2+5x-3=0$

We need to determine the solution of the equation.

The solution of the equation can be determined using the quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Hence, from the equation, we have,

$a=-1,\:b=5,\:c=-3$

Substituting these values in the quadratic formula, we get,

$x=\frac{-5\pm \sqrt{5^2-4\left(-1\right)\left(-3\right)}}{2\left(-1\right)}$

Simplifying, we get,

$x=\frac{-5\pm \sqrt{25-12}}{-2}$

Simplifying the terms within the root, we get,

$x=\frac{-5\pm \sqrt{13}}{-2}$

Thus, the roots of the equation are $x=\frac{-5+ \sqrt{13}}{-2}$ and $x=\frac{-5- \sqrt{13}}{-2}$

Taking out the negative sign, we get,

$x=\frac{-(5- \sqrt{13})}{-2}$ and $x=\frac{-(5+ \sqrt{13})}{-2}$

Cancelling the negative sign, we get,

$x=\frac{5-\sqrt{13}}{2}$ and $x=\frac{5+\sqrt{13}}{2}$

Thus, the solutions of the equation are $x=\frac{5-\sqrt{13}}{2}$ and $x=\frac{5+\sqrt{13}}{2}$

7 0

3 years ago

PLEASE HELP!!!!!!!!!​

PLEASE HELP!!!!!!!!!