Answer:
Nice picture
Step-by-step explanation:
utoo............
The answer is (7, -26) for The second endpoint.
We'll call the midpoint M. In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.
(Ux + Vx)/2 = Mx
(Vx + 3)/2 = 5
Vx + 3 = 10
Vx = 7
And now we do the same thing for y values
(Uy + Vy)/2 = My
(Vy + 6)/2 = -10
Vy + 6 = -20
Vy = -26
This gives us the final point of (7, -26)
Answer:
Any points on the line y=2/5 x - 6/5. See picture below.
Step-by-step explanation:
Convert the equation to slope intercept form and graph it.
2x - 5y = 6
-5y = 6 - 2x
y = -2/-5 x + 6/-5
y=2/5 x - 6/5.
Locate each of the points listed on the graph. If they are a part of the line, then they are solutions.
Thet contradict each other, that's why both of them are incorrect.
<span>Suppose that a polynomial has four roots: s, t, u, and v. If the polynomial were evaluated at any of these values, it would have to be zero. Therefore, the polynomial can be written in this form.
p(x)(x - s)(x - t)(x - u)(x - v), where p(x) is some non-zero polynomial
This polynomial has a degree of at least 4. It therefore cannot be cubic.
Now prove Kelsey correct. We have already proved that there can be no more than three roots. To prove that a cubic polynomial with three roots is possible, all we have to do is offer a single example of that. This one will do.
(x - 1)(x - 2)(x - 3)
This is a cubic polynomial with three roots, and four or more roots are not possible for a cubic polynomial. Kelsey is correct.
Incidentally, if this is a roller coaster we are discussing, then a cubic polynomial is not such a good idea, either for a vertical curve or a horizontal curve. I hope this helps</span><span>
</span>
Answer:
It is. Only you dont get a whole number.
Step-by-step explanation:
