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2 years ago

Write a coordinate proof given quadrilateral ABCD with vertices A (3, 2), B (8, 2), C (5, 0), and D (0, 0).

Mathematics

1 answer:

EleoNora [17]2 years ago

4 0

Answer:

Step-by-step explanation:

There is really no way to show that of I know of without drawing it but here is this. I hope this helps and not really exact on position but that is very close.

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How do i show the work? please help!

asambeis [7]

Tigers: 1 - 2/3 = .3333

Redbirds: 1 - 4/5 = .2

Bulldogs: 1 - 3/8 = .625

Titans: 1 - 1/2 = .5

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B is the correct answer.

7 0

2 years ago

3.62 the 3 stands for Math

viva [34]

The 3 represents a whole number.
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2 years ago

1. Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer t

Mazyrski [523]

Answer:

Part (A): The required inequality is T < 35 or t >40.

Part (B): The correct option is C) Only x=7.

Part (C) |x+1|+5=2 has no solution; |4x+12|=0 has one solution; |3x|=9 has two solution.

Step-by-step explanation:

Consider the provided information.

Part (A)

Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer than 40°F is an unsafe food practice.

The union is written as A∪B or “A or B”.

The intersection of two sets is written as A∩B or “A and B”

We need to determine the inequalities represent the union of these improper storage.

That means we will use A∪B or “A or B”.

The improper storage temperatures is when temperature is less than 35°F or greater than 40°F.

Hence, the required inequality is T < 35 or t >40.

Part (B) 15| x-7|+4=10|x-7|+4

Solve the inequality as shown below:

Subtract 4 from both sides.

$15| x-7|+4-4=10|x-7|+4-4$

Subtract 10|x-7| from both sides

$5\left|x-7\right|=0\\\left|x-7\right|=0\\x=7$

Hence, the correct option is C) Only x=7.

Part (C) Match the solution,

$\left|x+1\right|+5=2$

Subtract 2 from both sides.

$\left|x+1\right|=-3$

Absolute value cannot be less than 0.

Hence, |x+1|+5=2 has no solution.

$|4x+12|=0$

$4x+12=0$

$x=-3$

Hence, |4x+12|=0 has one solution.

$|3x|=9$

$\mathrm{If}\:|u|\:=\:a,\:a>0\:\mathrm{then}\:u\:=\:a\:\quad \mathrm{or}\quad \:u\:=\:-a$

$3x=-9\quad \mathrm{or}\quad \:3x=9\\x=-3\quad \mathrm{or}\quad \:x=3$

Hence, |3x|=9 has two solution.

3 0

3 years ago

I need to solve: 6x+3^59

MrMuchimi

6х=59:3
6х=19,6
Х=19,6:6
Х=3,2

7 0

3 years ago

Given the right triangle shown below.if Cos A =15/17 and tan A=8/15 which of the following represents the length of BC

otez555 [7]

Answer:

The Figure for Right triangle is below,

Therefore , 15 unit length represents BC.

Step-by-step explanation:

Given:

Consider a right triangle ABC, Such that

$\cos A=\dfrac{15}{17}\\\\\tan A=\dfrac{8}{15}$

To Find:

BC = ?

Solution:

In Right Angle Triangle ABC, Cosine and Tangent identity

$\cos A = \dfrac{\textrm{side adjacent to angle C}}{Hypotenuse}\\$

$\tan A= \dfrac{\textrm{side opposite to angle A}}{\textrm{side adjacent to angle A}}$

BUT,

$\cos A=\dfrac{15}{17}\\\\\tan A=\dfrac{8}{15}$ ....Given

On Comparing,

Adjacent side to angle A = AB = 15

Opposite side to angle A = BC = 8

Hypotenuse = AC =17

Also Pythagoras theorem is Satisfies,

$(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}$

$(\textrm{Hypotenuse})^{2} = 17^{2}=289$

$(\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}=15^{2}+8^{2}=289$

The Figure for Right triangle is below,

Therefore , 15 unit length represents BC.

7 0

2 years ago