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3 years ago

Write a coordinate proof given quadrilateral ABCD with vertices A (3, 2), B (8, 2), C (5, 0), and D (0, 0).

Mathematics

1 answer:

EleoNora [17]3 years ago

4 0

Answer:

Step-by-step explanation:

There is really no way to show that of I know of without drawing it but here is this. I hope this helps and not really exact on position but that is very close.

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What is the answer to this equation?

pochemuha

This is the answer 46.87016903609025

6 0

3 years ago

6x^2-9x +2=0 solve the quadratic equation using the quadratic formula

balu736 [363]

<u>ANSWER: </u>

The roots of $6 x^{2}-9 x+2=0$ are $\frac{9+\sqrt{33}}{4}, \frac{9-\sqrt{33}}{4}$

<u>SOLUTION:</u>

Given, quadratic equation is $6 x^{2}-9 x+2=0$ --- eqn (1)

We need to find the roots of given quadratic equation using quadratic formula.

Quadratic formula for general quadratic equation $a x^{2}+b x+c=0$ is $X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for eqn (1) a = 6, b= -9 and c = 2

$X=\frac{-(-9) \pm \sqrt{(-9)^{2}-4 \times6 \times 2}}{2 x 2}$

$X=\frac{9 \pm \sqrt{81-48}}{4}$

$\begin{array}{l}{X=\frac{9 \pm \sqrt{33}}{4}} \\ {X=\frac{9+\sqrt{33}}{4}, \frac{9-\sqrt{33}}{4}}\end{array}$

Hence the roots of $6 x^{2}-9 x+2=0$ are $\frac{9+\sqrt{33}}{4}, \frac{9-\sqrt{33}}{4}$

6 0

3 years ago

Please help it’s geometry will mark brainliest!

Dima020 [189]

Answer:

its 216

Step-by-step explanation:

when it's one the edge the arc is double the angle

5 0

3 years ago

Wilbur's Bean Emporium serves barbeque sandwiches over the lunch hour. The marginal cost of the 50 th barbeque sandwich is $1.50

Nikitich [7]

Answer:

Step-by-step explanation:

4 0

4 years ago

Personal best finishing times for a particular race in high school track meets are normally distributed with mean 24.6 seconds a

Dovator [93]

Answer: the qualifying time in seconds is about 25.3

Step-by-step explanation:

Since the personal best finishing times for a particular race in high school track meets are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = personal best finishing times for a particular race.

µ = mean finishing time

σ = standard deviation

From the information given,

µ = 24.6 seconds

σ = 0.64 seconds

The probability value for the top 15% of finishing time for runners to qualify would be (1 - 15/100) = (1 - 0.15) = 0.85

Looking at the normal distribution table, the z score corresponding to the probability value is 1.04

Therefore,

1.04 = (x - 24.6)/0.64

Cross multiplying by 0.64, it becomes

1.04 × 0.64 = x - 24.6

0.6656 = x - 24.6

x = 0.6656 + 24.6

x = 25.3 seconds

8 0

3 years ago