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2 years ago

Write a coordinate proof given quadrilateral ABCD with vertices A (3, 2), B (8, 2), C (5, 0), and D (0, 0).

Mathematics

1 answer:

EleoNora [17]2 years ago

4 0

Answer:

Step-by-step explanation:

There is really no way to show that of I know of without drawing it but here is this. I hope this helps and not really exact on position but that is very close.

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You collect a total of $75 in donations from three people. The three donations are in the ratio 4 to 4 to 7. How much is each of

worty [1.4K]

Each smaller donation was for $20 The largest donation was $15 greater than the smaller donation. First, determine the size of each donation. Since they are in a ratio of 4:4:7, it's easiest to add the ratios together (4+4+7) = 15. Then divide the total donation by that sum (75/15) = 5. Finally, multiply 5 by each of the ratios. 5 * 4 = 20, 5 * 4 = 20, and 5 * 7 = 35 So the 2 smaller donations were $20 each, and the largest donation was for $35. The largest donation was $35 - $20 = $15 larger than one of the smaller donations.

7 0

2 years ago

Semicircles

Studentka2010 [4]

Answer:

The area of the shaded portion of the figure is $9.1\ cm^2$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shaded area is equal to the area of the square less the area not shaded.

There are 4 "not shaded" regions.

step 1

Find the area of square ABCD

The area of square is equal to

$A=b^2$

where

b is the length side of the square

we have

$b=4\ cm$

substitute

$A=4^2=16\ cm^2$

step 2

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):

The area of circle is equal to

$A=\pi r^{2}$

The diameter of the circle is equal to the length side of the square

$r=\frac{b}{2}=\frac{4}{2}=2\ cm$ ---> radius is half the diameter

substitute

$A=\pi (2)^{2}$

$A=4\pi\ cm^2$

Therefore, the area of 2 "not-shaded" regions is:

$A=(16-4\pi) \ cm^2$

and the area of 4 "not-shaded" regions is:

$A=2(16-4\pi)=(32-8\pi)\ cm^2$

step 3

Find the area of the shaded region

Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:

$A=16-(32-8\pi)=(8\pi-16)\ cm^2$

---> exact value

assume

$\pi =3.14$

substitute

$A=(8(3.14)-16)=9.1\ cm^2$

8 0

2 years ago

a painter can paint 20 windows in one day. If he has to paint 50 pairs of windows how much time will he take to paint

vazorg [7]

Answer:

50*2=100

100/20=5

The answer is 5 days!

5 0

2 years ago

Which of the following polygons is not a regular polygon?

Shkiper50 [21]

Answer:

Step-by-step explanation:

polygons is a plane figure that is described by a finite number of straight line segments connected to form a closed polygonal chain or polygonal circuit

6 0

1 year ago

What fraction represents the decimal 0.12

Lelechka [254]

3/25 is your answer

12/100-->

6/50-->

=3/25

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers