There is 8 more girls in the class than boys. (I’m pretty sure this is correct because I had this same question)
Answer:
24, -38, 62, -100
Step-by-step explanation:
The recursive formula is a_n = a_(n-2) - a_(n-1)
so. we try this 4 times after the -14 term
a_3 = -4 = 2 - 6 = a_1 - a_2
...
a_6 = a_4 - a_5 = 10 - (-14) = 24
a_7 = a_5 - a_6 = -14 - (24) = -38
a_8 = a_6 - a_7 = 24 - (-38) = 62
a_9 = a_7 - a_8 = -38 - 62 = -100
a_10 = a_8 - a_9 = 62 - (-100) = 162
Negative abscissa, zero ordinate is between Quadrant II and Quadrant III.
Hope this helps! :)
log (m + n) = log m+ log n and proved it m =n/n-1
Given;
If log (m + n) = log m+ log n
To show that the m =n/n-1
Now, According to the question:
We know that,
Log (m + n) = log m + log n
Log (m + n ) = log (mn). [log a + log b = log ab ]
Cancelling the log on both sides.
then,
m + n = mn
=> n = mn - m
=> n = m (n - 1)
=> m = n / n - 1
Hence Proved
log (m + n) = log m+ log n and proved it m =n/n-1
What is Logarithm?
A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.
Learn more about Logarithm at:
brainly.com/question/16845433
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Idk if this will help but here. Thirty six divided by four equals nine.
