Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:
0.2 = 2/9
Step-by-step explanation:
Hope my answer has helped you!
The distance between the Earth's surface and the upper edge of the Earth's atmosphere would be Q - V.
The distance from the Sun to the Earth is Q. The distance from the Sun to the upper edge of the atmosphere is V. If you subtract V from Q, the remaining distance is that of the Earth's atmosphere. Q - V = the atmosphere
Answer:
Step-by-step explanation:
Let the number be x,
2x+4 = 3x-7
Collect like terms
2x-3x= -4-7
-x =. -11
Multiply both sides by -1
x. =. 11
PLEASE MARK BRAINLIEST.
