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Dennis_Churaev [7]
3 years ago
5

Find the range of the data in the box plot below.​

Mathematics
1 answer:
harkovskaia [24]3 years ago
8 0

Answer:

im pretty sure its 2

Step-by-step explanation:

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If AC=12, BC=3, find CE<br> 1) 3 square root of 3<br> 2) 6<br> 3) 18
azamat

Answer:

2) 6

Step-by-step explanation:

CE^2 = BC * AC

CE^2 = 3 * 12

CE^2 = 36

CE = 6

7 0
3 years ago
Read 2 more answers
Solve using the square root property.X^2=-12
Alla [95]

Answer:

x = ± 2i\sqrt{3}

Step-by-step explanation:

note that \sqrt{-1} = i

x² = - 12 ( take square root of both sides )

x = ± \sqrt{-12} = ± \sqrt{4(3)(-1)} = ± 2i\sqrt{3}

5 0
2 years ago
Estimate the limit<br><br> A <br> B <br> C<br> D
Lera25 [3.4K]

Answer:

C. \lim_{x\rightarrow f(x)=2

Step-by-step explanation:

Given problem is \lim_{x\rightarrow \frac{\pi}{4}}\frac{tan(x)-1}{x-\frac{\pi}{4}}.

Now we need to evaluate the given limit.

If we plug \x=\frac{\pi}{4}, into given problem then we will get 0/0 form which is an indeterminate form so we can apply L Hospitals rule

take derivative of numerator and denominator

\lim_{x\rightarrow \frac{\pi}{4}}\frac{tan(x)-1}{x-\frac{\pi}{4}}

=\lim_{x\rightarrow \frac{\pi}{4}}\frac{sec^2(x)-0}{1-0}

=\frac{sec^2(\frac{\pi}{4})-0}{1-0}

=\frac{(\sqrt{2})^2}{1}

=\frac{2}{1}

=2

Hence choice C is correct.

5 0
3 years ago
The scale on a map is 1 in. :25 mi. Your measure 6.5 in. Between two towns. What is the actual distance?
pshichka [43]

Answer:

162.5mi

Step-by-step explanation:

If the scale of the map is 1in:25mi, and you measure 6.5in between two twoms, then the real distance would be 6.5in*25mi = 162.5mi.

6 0
3 years ago
How do you know what to split 26 into ?
madam [21]

Answer:

see explanation

Step-by-step explanation:

Assuming you are factoring the expression

Given

4y² + 26y + 30 ← factor out 2 from each term

= 2(2y² + 13y + 15) ← factor the quadratic

Consider the factors of the product of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term.

product = 2 × 15 = 30 and sum = 13

the factors are 10 and 3

Use these factors to split the y- term

2y² + 10y + 3y + 15 ( factor the first/second and third/fourth terms )

= 2y(y + 5) + 3(y + 5) ← factor out (y + 5) from each term

= (y + 5)(2y + 3)

Thus

4y² + 26y + 30

= 2(y + 5)(2y + 3)

5 0
3 years ago
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