We know that pupils are students
Students = S
boys = B
Teachers = T
So....
S = 8T
Boys = 3G
T = B - 70
Since there is 8x students than teachers, I did Boys = 6x and girls = 2x
I'm going to use this next: S = 8T
8x = 8(B -70)
8x = 8(6x - 70)
8x = 4x - 560
x = 14
We know there is 8x students, so there are 112 students and we know that there is 1/8 of teachers, so there are 14 teachers.
Answer = 126.
.1x+.2y=-1
.5x-.9y=6.4
×-5 equation .1x+.2y=-1
-.5x-y=5
.5x-.9y=6.4
solve by elimination
-1.9y=11.4
÷-1.9 both sides
y=-6
solve for X
.1x+.2 (-6)=-1
.1x-1.2=-1
+1.2 both sides
.1x=.2
÷ 1 both sides
x=2
plug into 2nd equation to see if it's true
x=2
y=-6
0.5(2)-0.9(-6)=6.4
1+5.4=6.4
6.4=6.4 answers hold true
The question is not exhaustive.
Answer:
-48-22i
Step-by-step explanation:
<span>12*(4x−5)/52=10 if this is the equation
the value for x would be
x </span>≈ 12
