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siniylev [52]
3 years ago
15

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
RideAnS [48]3 years ago
3 0

Answer:

73 - 2x = 86 - 3x

So 3x - 2x =86 - 73 so x=13

Step-by-step explanation:

Then m<1 = 73-2(13) = 47

M<2=82-3(13)=47

So both angles are having same value

Please Brainlist me

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You have heard that customers will try a new caterer if the price is 20% below their existing caterer. Your competitor prices a
Evgesh-ka [11]

Answer:

b) $640

Step-by-step explanation:

Competitor's price  = $800

<u>Price, 20% below of competitor's:</u>

  • $800 - 20% =
  • $800*(100-20)/100 =
  • $800*0.8 =
  • $640

Correct answer choice is b) $640

3 0
3 years ago
What is 802.6 in expanded form
ankoles [38]

Answer:

802+6 tenths.

Step-by-step explanation:

802 is not apart of the decimal. (I might sound stupid but I dont remember expanded form as much.) Only the 6 is apart of the decimal itself. 802 is just numbers. The 6 is pretty much the decimal.

4 0
4 years ago
HURRY PLEASE HELP!!
Bad White [126]
Hope you get this right I just need to answer this so I can ask a question
7 0
3 years ago
3 + 3m = 2m + 3<br><br> please send me the work i would appreciate it. asap
givi [52]

Answer:

the answer is 0

Step-by-step explanation:

(sorry don't have time to type it out)

4 0
3 years ago
Read 2 more answers
Problem 5. Buses arrive at 116th and Broadway at the times of a Poisson arrival process with intensity λ arrivals per hour. Thes
Shtirlitz [24]

Answer:

Step-by-step explanation:

The problem states that there are only two types of busses - M104 and M6 with probable occurence of 0.6 and 0.4 respectively.

If the average number of busses arriving per hour is λ, the average number of M6 busses per hour is  0.4λ

Now consider a set of 3 M6 busses as an event. The average number of such events per hour will be

μ = 0.4λ / 3

The expected number of hours for the event "THIRD M6 arrives", let's say X is

E[X] = 1 / μ ( exponential distribution) = 3 / 0.4λ

= 7.5 / λ

The variance of event X is =

Var[x] = \frac{1}{U^2} = \frac{56.25}{\lambda ^2}

6 0
3 years ago
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