Answer:
b) $640
Step-by-step explanation:
Competitor's price = $800
<u>Price, 20% below of competitor's:</u>
- $800 - 20% =
- $800*(100-20)/100 =
- $800*0.8 =
- $640
Correct answer choice is b) $640
Answer:
802+6 tenths.
Step-by-step explanation:
802 is not apart of the decimal. (I might sound stupid but I dont remember expanded form as much.) Only the 6 is apart of the decimal itself. 802 is just numbers. The 6 is pretty much the decimal.
Hope you get this right I just need to answer this so I can ask a question
Answer:
the answer is 0
Step-by-step explanation:
(sorry don't have time to type it out)
Answer:
Step-by-step explanation:
The problem states that there are only two types of busses - M104 and M6 with probable occurence of 0.6 and 0.4 respectively.
If the average number of busses arriving per hour is λ, the average number of M6 busses per hour is 0.4λ
Now consider a set of 3 M6 busses as an event. The average number of such events per hour will be
μ = 0.4λ / 3
The expected number of hours for the event "THIRD M6 arrives", let's say X is
E[X] = 1 / μ ( exponential distribution) = 3 / 0.4λ
= 7.5 / λ
The variance of event X is =
![Var[x] = \frac{1}{U^2} = \frac{56.25}{\lambda ^2}](https://tex.z-dn.net/?f=Var%5Bx%5D%20%3D%20%5Cfrac%7B1%7D%7BU%5E2%7D%20%3D%20%5Cfrac%7B56.25%7D%7B%5Clambda%20%5E2%7D)