(2^8 x 3^-5 x 6^0) x [(3^-2/2^3) x 2^28] = x
(256 x .004 x 1) x [(.111/8) x 268,435,456] = x
(1.024 x 1) x .(0138 x 268,435,456) = x
1.024 x (.0138 x 268,435,456) = x
1.024 x 3,704,409.2928 = x
3,793,315.1158272 = x
Correct me if I am wrong. :)
Let Y = total cost of both schools.
The total cost would be ( number of credits at Westside x 98) + (number of credits at Pinewood x 115).
The total number of credits he is taking is 14.
If w is the number of credits at Westside, then for Westside you have 98w ( $98 times the number of credit hours)
The equation is now y = 98w + (number of credits at Pinewood x 115).
The number of credit hours at Pinewood would be the total credit hours 14 minus the credit hours at Westside w, so you have 14-w, which needs to be multiplied by the cost at Pinewood.
The equation is now y = 98w + 115(14-w)
This can be simplified using the distributive property to:
Y = 98w + 1610 - 115w
Y = -17w + 1610
Answer:
9280?
Step-by-step explanation:
Just multiply 1160 x 8
Answer:
solution
x<2,2x<-4,x-2<-4 are equvalent
but x-2<4 is not
