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Alexxandr [17]
3 years ago
15

Solve 3(x-4)=-5 for x​

Mathematics
2 answers:
makvit [3.9K]3 years ago
8 0

Answer:

x=7/3

Step-by-step explanation:

3(x-4)=-5

3x-12=-5

3x=7

x=7/3

anyanavicka [17]3 years ago
6 0

3(x-4)=-5

3x-12=-5  add 12 to both sides

3x=7 divide both sides by 3

x=7/3

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yan [13]

these are the answers to all systems

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3 years ago
Use implicit differentiation to find the points where the parabola defined by x2−2xy+y2+4x−8y+20=0 has horizontal and vertical t
Komok [63]

Answer:

The parabola has a horizontal tangent line at the point (2,4)

The parabola has a vertical tangent line at the point (1,5)

Step-by-step explanation:

Ir order to perform the implicit differentiation, you have to differentiate with respect to x. Then, you have to use the conditions for horizontal and vertical tangent lines.

-To obtain horizontal tangent lines, the condition is:

\frac{dy}{dx}=0 (The slope is zero)

--To obtain vertical tangent lines, the condition is:

\frac{dy}{dx}=\frac{1}{0} (The slope is undefined, therefore the denominator is set to zero)

Derivating respect to x:

\frac{d(x^{2}-2xy+y^{2}+4x-8y+20)}{dx} = \frac{d(x^{2})}{dx}-2\frac{d(xy)}{dx}+\frac{d(y^{2})}{dx}+4\frac{dx}{dx}-8\frac{dy}{dx}+\frac{d(20)}{dx}=2x -2(y+x\frac{dy}{dx})+2y\frac{dy}{dx}+4-8\frac{dy}{dx}= 0

Solving for dy/dx:

\frac{dy}{dx}(-2x+2y-8)=-2x+2y-4\\\frac{dy}{dx}=\frac{2y-2x-4}{2y-2x-8}

Applying the first conditon (slope is zero)

\frac{2y-2x-4}{2y-2x-8}=0\\2y-2x-4=0

Solving for y (Adding 2x+4, dividing by 2)

y=x+2 (I)

Replacing (I) in the given equation:

x^{2}-2x(x+2)+(x+2)^{2}+4x-8(x+2)+20=0\\x^{2}-2x^{2}-4x+x^{2} +4x+4+4x-8x-16+20=0\\-4x+8=0\\x=2

Replacing it in (I)

y=(2)+2

y=4

Therefore, the parabola has a horizontal tangent line at the point (2,4)

Applying the second condition (slope is undefined where denominator is zero)

2y-2x-8=0

Adding 2x+8 both sides and dividing by 2:

y=x+4(II)

Replacing (II) in the given equation:

x^{2}-2x(x+4)+(x+4)^{2}+4x-8(x+4)+20=0\\x^{2}-2x^{2}-8x+x^{2}+8x+16+4x-8x-32+20=0\\-4x+4=0\\x=1

Replacing it in (II)

y=1+4

y=5

The parabola has vertical tangent lines at the point (1,5)

4 0
4 years ago
Which of the following expressions is equivalent to 4^-3?<br><br> ​
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Answer:

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Step-by-step explanation:

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3 years ago
Someone answer. Will give brainlest
Leto [7]

Area inside the semi-circle and outside the triangle is  (91.125π - 120) in²

Solution:

Base of the triangle = 10 in

Height of the triangle = 24 in

Area of the triangle = \frac{1}{2} bh

                                $=\frac{1}{2} \times 10\times24

Area of the triangle = 120 in²

Using Pythagoras theorem,

\text{Hypotenuse}^2=\text{base}^2+\text{height}^2

\text{Hypotenuse}^2=10^2+24^2

\text{Hypotenuse}^2=100+576

\text{Hypotenuse}^2=676

Taking square root on both sides, we get

Hypotenuse = 23 inch = diameter

Radius = 23 ÷ 2 = 11.5 in

Area of the semi-circle = \frac{1}{2}\pi r^2

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Area of the semi-circle = 91.125π in²

Area of the shaded portion = (91.125π - 120)  in²

Area inside the semi-circle and outside the triangle is  (91.125π - 120)  in².

5 0
3 years ago
Please help! :Find the measure of angle y
frozen [14]

Answer:

75

Step-by-step explanation:

showing that  the two lines are proportinal based on their markings, it shows that x=55, and then you just do 180-(55+50), which is 75

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3 years ago
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