A car traveling at 23 mi/h accelerates to 46 mi/h in 5 seconds. It maintains that speed for 5 seconds and then slows to a stop i
n 5 seconds. Sketch and label a graph showing the car’s speed over time
1 answer:
Answer:
It is given that a car traveling at 23 mi/h accelerates to 46 mi/h in 5 seconds.
This means that in 5 seconds it's speed continuously increases to reach 46 mi/h from 23 mi/h.
It maintains that speed for 5 seconds and then slows to a stop in 5 seconds.
This means that the speed of the car is constant i.e. 46 mi/h i.e. the graph is a straight horizontal line parallel to the time axis.
And then it decreases to reach 0 mi/h.
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Refer to the diagram shown below.
The velocity of the person on the walkway relative to the ground is the velocity of the walkway (relative to the ground) plus the velocity of the person relative to the walkway.
It is
1.0 + 0.5 = 1.5 m/s
The person on the ground moves at - 0.2 m/s, which is in the opposite direction to that of the walkway and the person on the walkway.
Therefore the velocity of the person on the walkway relative to the person on the ground is
105 - (-0.2) = 1.7 m/s
Answer: 1.7 m/s
The velocity of the person on the walkway relative to the ground is the velocity of the walkway (relative to the ground) plus the velocity of the person relative to the walkway.
It is
1.0 + 0.5 = 1.5 m/s
The person on the ground moves at - 0.2 m/s, which is in the opposite direction to that of the walkway and the person on the walkway.
Therefore the velocity of the person on the walkway relative to the person on the ground is
105 - (-0.2) = 1.7 m/s
Answer: 1.7 m/s