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kobusy [5.1K]
2 years ago
13

A car traveling at 23 mi/h accelerates to 46 mi/h in 5 seconds. It maintains that speed for 5 seconds and then slows to a stop i

n 5 seconds. Sketch and label a graph showing the car’s speed over time

Mathematics
1 answer:
Nataliya [291]2 years ago
5 0

Answer:

It is given that a car traveling at 23 mi/h accelerates to 46 mi/h in 5 seconds.

This means that in 5 seconds it's speed continuously increases to reach 46 mi/h from 23 mi/h.

It maintains that speed for 5 seconds and then slows to a stop in 5 seconds.

This means that the speed of the car is constant i.e. 46 mi/h i.e. the graph is a straight horizontal line parallel to the time axis.

And then it decreases to reach 0 mi/h.

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Divide: (-7x+x^2+15)÷(-3+x)
kakasveta [241]
Since the divisor is in the form (x + #) or (x - #), This can be done by synthetic division.
First put the polynomial ion descending order: x^2 - 7x + 15
Take the coefficients of the terms and follow these steps:

3 |  1 -7  15
         3  -12
___________  Bring down the 1, multiply the 3 by the 1 and place under the
     1  -4    3       -7, then add.
                         Multiply 3 by -4, place under the 15, then add.
       The bottom row is our answer. Since the problem started with a second power, the answer will start with a first power.
The bottom row are the coefficients of the terms and the last number is the remainder.
x - 4 remainder 3 ALSO WRITTEN   x - 4 + 3/(x -3)
3 0
3 years ago
A person on a runway sees a plane approaching. The angle of elevation from the runway to the plane is 11.1° . The altitude of th
Gnoma [55]

Answer:

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner.  The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

\tan\theta=\frac{Perpendicular}{base}

Here, \theta=11.1^{\circ} ,Perpendicular AB = 4000

\tan\theta=\frac{AB}{BC}

\tan 11.1^{\circ} =\frac{4000}{BC}

Solving for BC, we get,

BC=\frac{4000}{\tan 11.1^{\circ} }

BC=\frac{4000}{0.196} (approx)

BC=20408.16(approx)  

Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

8 0
2 years ago
Hey can you please help me posted picture of question
Sergeeva-Olga [200]
Total number of chips = 4+ 6 = 10
Number of white chips = 4

Probability of picking a white chip = \frac{4}{10}= \frac{2}{5}

This white chip is not replaced back into the bag. This will reduce the number of white chips in the bag by 1 and reduce the total number of chips in the bag by 1.

So, now the total number of chips in the bag = 3 + 6 = 9
Number of white chips in the bag = 3

Probability of picking a white chip = \frac{3}{9}= \frac{1}{3}

Thus, the probability of picking two white chips will be = \frac{2}{5}* \frac{1}{3}= \frac{2}{15}

Therefore, option B gives the correct answer.
3 0
3 years ago
Given y+2x+7, write an equation whose graph is shifted 3 units to the right. Thank you!
ddd [48]

Answer:

y=2x+1

Step-by-step explanation:

To find the answer, first graph the equation and find coordinates for atleast 2 points. We can find (0,7) and (1,9). Next we add 3 to the x coordinate of each point. We get (3,7) and (4,9). We know the slope which is 2. So our equation becomes y=2x+b. Next we substitube a coordinate pair, with y and x in the equation. We get 7=2*3+b. Solve and we get 1=b.

Therefore,

y=2x+1.

I hope this helps.

6 0
2 years ago
Find the measure of each angle.
Marrrta [24]
90= 3x + 2x
90= 5x
x= 18
one measure = 3(18)= 54
the other one= 2(18)= 36
hope this helps!
5 0
2 years ago
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