<span>Google
Glass was interesting; a personal screen overlaid onto the real world,
with 'augmented reality' ideas. The Nintendo 3DS was the first 'no
glasses' portable 3D system.
So I predict Google 3D Glasses with built in Dolby 9.1 sound emulation. </span>
Answer:
Answer is
By topic, By collection.
Refer below.
Explanation:
Quick SearchLinks to an external site. lets you refine or narrow your search results using links on the right side of the screen. Do a search on wind power. Some criteria that can refine your search results in Quick Search are:
By topic
By collection
If you have 10 bits available then you can interpret any number in range ![[0,2^{10}-1]=[0,1023]](https://tex.z-dn.net/?f=%5B0%2C2%5E%7B10%7D-1%5D%3D%5B0%2C1023%5D)
.
The system therefore could represent the actual temperature of 39°C.
Hope this helps.
Answer:
#include <iostream>
#include <stack>
#include <queue>
#include <string>
int main()
{
while ( true )
{
std::string letters;
std::cout << "Please enter a word (Enter - exit): ";
std::getline( std::cin, letters );
if ( letters.empty() ) break;
std::stack<char>
s( std::stack<char>::container_type( letters.begin(), letters.end() ) );
std::queue<char>
q( std::queue<char>::container_type( letters.begin(), letters.end() ) );
while ( !s.empty() && s.top() == q.front() )
{
s.pop();
q.pop();
}
if ( s.empty() ) std::cout << "The word is a palindrome" << std::endl;
else std::cout << "The word is not a palindrome" << std::endl;
}
return 0;
}
Explanation:
A <em>stack</em> is used to replicate a stack data structure in C++ while <em>Queue </em>container is a replica of the queue data structure in C++, Unlike stack, in the queue container, there are two ends, i.e. front, and back.
In the code above to be able to use used stack and queue, we included the headers #include <stack> and#include <queue>.
Answer:
The solution code is written in Python 3
- digits = input("Enter 9 digits: ")
-
- multiplier = 1
- total = 0
-
- for x in digits:
- total += int(x) * multiplier
- multiplier += 1
-
- checksum = total % 11
-
- if(checksum == 10):
- print(digits + "X")
- else:
- print(digits + str(checksum))
Explanation:
Firstly, use input function to get user input for 9 digits (Line 1)
Next we can use a for-loop to estimate the summation (d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5+ d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9) ( Line 6-8)
Then only apply % operator to get the remainder of total and get the checksum (Line 10)
Next create if and else statement to print the digits string joined with X if checksum is 10 else join digits string with checksum value (Line 12 -15)
