Here we are to find the values of x in which the function
f (x) = csc 5x is discontinuous. What this usually means is to find when the
value approaches infinity.
We know from trigonometric identities that csc is the
equivalent to 1 / sin, therefore the function in terms of sin is:
f(x) = 1 / sin 5x
We can see that the function becomes discontinuous when sin
5x = 0, that is a value divided by 0 is discontinuous or approaches infinity.
sin 5x is equal to zero when:
5x = 0 or π
So given k as an arbitrary integer
5x = k π
So k can be: k = 0, 1, 2
x = k π/ 5
Answer:
x=17
Step-by-step explanation:
7x+15=4x+66
3x=51
x=17
I think it’s B
Sorry if I’m wrong
The equation of the parabola in <em>standard</em> form whose vertex is (0, 0) and a focus along the <em>negative</em> part of the x-axis is equal to x² = - 6 · y. (Correct choice: D)
<h3>How to determine the best equation of the parabola based on given characteristics</h3>
In accordance with the statement, we find that the parabola has its vertex at the origin, therefore it is <em>horizontal</em> and its <em>vertex</em> constant (C) is <em>negative</em> as its focus is in the <em>negative</em> part of the x-axis. Therefore, the equation of the parabola in <em>standard</em> form has the following form:
x² = C · y, for C < 0. (1)
In consequence, the equation of the parabola in <em>standard</em> form whose vertex is (0, 0) and a focus along the <em>negative</em> part of the x-axis is equal to x² = - 6 · y.
To learn more on parabolae: brainly.com/question/21685473
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3/10•(2 5/6)
=3/10•(17/6)
=51/60