Evaluate the following expression.<br> 3×9+10× <br> {36}{6} <br>

In this question, we are tasked with calculating how much a certain value in a savings account that is earning an interest that is compounded annually will be worth.

To calculate this, we use the compound interest formula;

A = P( $(1+r/n)^{nt}$

Where A is the amount after that number of years which of course we want to calculate

P is the principal amount which is the amount we are investing which is $6439 according to the question

r is the interest rate which is 4% = 4/100 = 0.04

t is the time which is 8 years

n is 1 which is the number of times interest will be compounded annually

We plug these values as follows;

A = 6439(1 + 0.04/1)^8

A = 6439(1.04)^8

A = $8,812.22

This amount is greater then the needed $8,500 for the trip and of course it will be enough

8 0

3 years ago

Write an equation for the perpendicular line to the line whose equation is 4y-5x=20 that contains the point (-2,-3)

yuradex [85]

Answer:

4x + 5y = - 23

Step-by-step explanation:

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 4y - 5x = 20 into this form

add 5x to both sides

4y = 5x + 20 ( divide all terms by 4 )

y = $\frac{5}{4}$ x + 5 ← in slope-intercept form

with slope m = $\frac{5}{4}$

given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ , hence

$m_{perpendicular}$ = - 1 / $\frac{5}{4}$ = - $\frac{4}{5}$

y = - $\frac{4}{5}$ x + c ← is the partial equation

to find c substitute (- 2, - 3) into the partial equation

- 3 = $\frac{8}{5}$ + c ⇒ c = - $\frac{23}{5}$

y = - $\frac{4}{5}$ x - $\frac{23}{5}$ ← in slope-intercept form

multiply all terms by 5

5y = - 4x - 23 ( add 4x to both sides )

4x + 5y = - 23 ← in standard form

7 0

3 years ago

g If the economy improves, a certain stock stock will have a return of 23.4 percent. If the economy declines, the stock will hav

dusya [7]

Answer:

$E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%$

Now we can find the second central moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

$Sd(X) = \sqrt{275.5105}= 16.599 \%$

Step-by-step explanation:

We can define the random variable of interest X as the return from a stock and we know the following conditions:

$X_1 = 23.4 , P(X_1) =0.67$ represent the result if the economy improves

$X_2 = -11.9 , P(X_1) =0.33$ represent the result if we have a recession

We want to find the standard deviation for the returns on the stock. We need to begin finding the mean with this formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing the data given we got:

$E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%$

Now we can find the second central moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

$Sd(X) = \sqrt{275.5105}= 16.599 \%$

7 0

3 years ago

Evaluate the following expression. 3×9+10× {36}{6} ​

Evaluate the following expression. 3×9+10× {36}{6}