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Anastasy [175]
3 years ago
15

AC = Round your answer to the nearest hundredth.

Mathematics
1 answer:
garri49 [273]3 years ago
5 0

Answer:

the answer is 8.24 using tan =opp/adj

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2.5(6x -4) = 10+4(1.5+0.5x)
Lemur [1.5K]

Answer:

x = 2

Nothing more, nothing less

6 0
2 years ago
Simplify <br> cosx ( tanx+cotx)
Soloha48 [4]
The first step to solving this is to use tan(t) = \frac{sin(t)}{cos(t)} to transform this expression.
cos(x) × ( \frac{sin(x)}{cos(x)} + cot(x) )
Using cot(t) = \frac{cos(x)}{sin(x)},, transform the expression again.
cos(x) × ( \frac{sin(x)}{cos(x)} +  \frac{cos(x)}{sin(x)} )
Next you need to write all numerators above the least common denominator (cos(x)sin(x)).
cos(x) × \frac{sin(x)^{2} + cos(x)^{2}  }{cos(x)sin(x)}
Using sin(t)² + cos(t)² = 1,, simplify the expression. 
cos(x) × \frac{1}{cos(x)sin(x)}
Reduce the expression with cos(x).
\frac{1}{sin(x)}
Lastly,, use \frac{1}{sin(t)} = csc(t) to transform the expression and find your final answer.
csc(x)
This means that the final answer to this expression is csc(x).
Let me know if you have any further questions.
:)
4 0
3 years ago
All cars can be classified into one of four​ groups: the​ subcompact, the​ compact, the​ midsize, and the​ full-size. There are
Olegator [25]

Answer:

p value = 0.302

Step-by-step explanation:

Given that all cars can be classified into one of four​ groups: the​ subcompact, the​ compact, the​ midsize, and the​ full-size. There are five cars in each group. Head injury data​ (in hic) for the dummies in the​ driver's seat are listed below.

H_0: All cars have same mean values

H_a: atleast two cars have different mean values

(Two tailed anova test)

Anova: Single Factor      

     

SUMMARY      

Groups Count Sum Average Variance  

Subcompact 5 3444 688.8 48502.7  

compact 5 2879 575.8 4582.7  

Midsize 5 2534 506.8 18720.2  

Full size 5 2689 537.8 23905.2  

     

     

ANOVA      

Source of Variation SS df MS            F             P-value F crit

Between Groups 94825 3 31608.33 1.321    0.302           3.24

Within Groups 382843.2 16 23927.7    

     

Total 477668.2 19    

Since p value of 0.302 is greater than 0.05 significance level we accept null hypothesis.

p value = 0.302

6 0
2 years ago
A child 4.5 feet tall cast a 6 foot shadow a nearby statue casts a 12 foot shadow what is the height of the statue
neonofarm [45]

Answer: I believe it would be 9 feet tall.

Step-by-step explanation:

The statues shadow is 2 times larger than the childs shadow so you would multipy the childs height by 2

8 0
3 years ago
Read 2 more answers
There are 16 left-handed students in Ms. Tatum's class. The other 20 students in her class are right-handed.
tia_tia [17]

Answer:

I'm pretty sure the answer is about 44%

Step-by-step explanation:

6 0
3 years ago
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