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dimulka [17.4K]

3 years ago

6

trevor needs to let his puppy outside every quarter (1 fourth) hour to potty train him. draw and label a number line from 0 hour

s to 1 hour to show every 1 fourth hour.

1 answer:

Nastasia [14]3 years ago

7 0

Make a number line and make it into four parts that shows that <span>needs to let his puppy outside every 25 min.</span>

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I need help with this Algebra 1 Study Guide. It has 5 questions . This has many hard questions so to you people that like a chal

scoundrel [369]

1. Rational numbers can be written as a ratio (fraction)
Whole numbers are rational. 5 = 5/1, for example.
Square roots are NOT rational. Example: √3
However, square roots of square numbers can be simplified, and are therefore rational. <span>√4 = 2, rational.</span>

√4 + <span>√16 = 2 + 4 = 6. rational
</span>√5 + √36...<span> irrational
</span>√9 + <span>√24... irrational
</span>2 × <span>√4 = 2 × 2 = 4. rational
</span>√49 × <span>√81 = 7 × 9 = 63. rational
</span>3√12... irrational

2. $n^\frac12=\sqrtn$
$9^\frac32=9^3\times\frac12=\sqrt{9^3}=\sqrt{729}=29$

3. $\frac{n^a}{n^b}=n^{a-b}$

$\frac{a^\frac13}{a^\frac14}=a^{\frac13-\frac14}=a^{\frac{1}{12}}$

4. $n^\frac1x=\sqrt[x]n$

$\sqrt[3]{m^2n^5}=m^{\frac23}n^{\frac53}$

5. $\sqrt{a}\times\sqrt{b}=\sqrt{ab}$

$\sqrt{3}\times\sqrt{12}=\sqrt{3\times12}=\sqrt{36}=6$

A, since neither 3 nor 12 is a square but we end up with 6.

5 0

3 years ago

What’s the domain and range if this graph?

Kobotan [32]

Answer:

Step-by-step explanation:

4 0

4 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

Read 2 more answers

Two thirds of the families in smithville own their own homes. The total number of home owning families there is 480. How many fa

Leviafan [203]

X- the total number of families in Smithville<span>.
(2/3)x - the number of home owning families.
At the same time, </span> the number of home owning families is 480.

(2/3)x=480
x=480*3/2=720.

720 <span>families live in Smithville.</span>

8 0

3 years ago

Lily owed Megan $129.42. So far, she has paid Megan $32.56.

anzhelika [568]

Answer:

She still owes her $96.86

Step-by-step explanation:

Subtract 32.56 from 129.42

7 0

3 years ago