Answer:
The length of river frontage for each lot are 96.55 ft. 98.85 ft, 101.15 ft and 103.45 ft.
Step-by-step explanation:
See the attached diagram.
The river frontage of 400 ft will be divided into 84 : 86 : 88 : 90 for each lot as AP, BQ, CR, DS and ET all are parallel.
Therefore, PQ : QR : RS : ST = 84 : 86 : 88 : 90 = 42 : 43 : 44 : 45
Let, PQ = 42x, QR = 43x, RS = 44x and ST = 45x
So, (42x + 43x + 44x + 45x) = 400
⇒ 175x = 400
⇒ x = 2.2988.
So, PQ = 42x = 96.55 ft.
QR = 43x = 98.85 ft.
RS = 44x = 101.15 ft and
ST = 45x = 103.45 ft
(Answer)
Answer:
$6 per week (ratio 6/1)
Step-by-step explanation:
18/3=6
30/5=6
I have to interpret that:
1) the smaller square has side length = 3 cm
2) the bigger square has side length = 5 cm
3) the smaller square is completely inside the bigger square.
4) the points cannot be outside the bigger square
Under those assumptions the probability that a point is inside the smaller square is
P (inside the smaller square) = area of the smaller square / area of the bigger square
P (inside the smaller squere) = (3cm)^2 / (5cm)^2 = 9 / 25
Answer: 9 / 25
Answer:
1/8
Step-by-step explanation:
