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mart [117]
3 years ago
11

Enter your answer and show all the steps that you use to solve this problem.

Mathematics
1 answer:
avanturin [10]3 years ago
3 0

9514 1404 393

Answer:

  ∠B = 41°

Step-by-step explanation:

<u>Step 1</u>: Recognize that ∠B and ∠A are "remote interior angles" with respect to the exterior angle at C. Hence their sum will be equal to the measure of the exterior angle.

<u>Step 2</u>. Compute angle B as the difference between the exterior angle at C and the interior angle at A:

  113° - 72° = ∠B = 41°

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Evaluate the expression,<br> if x = 9, y = 3, and z = 5.<br> z2 • (x-y)
Bad White [126]

\huge\text{Hey there!}


\mathsf{z^2 \times (x - y)}

\mathsf{= 5^2 \times (9 - 3)}

\mathsf{= 5 \times 5 \times (9 - 3)}

\mathsf{= \bold{25}\times(9 - 3)}

\mathsf{= 25\times \bf 6}

\mathsf{= \bf 150}


\huge\text{Therefore, your answer should be: }

\huge\boxed{\frak{150}}\huge\checkmark


\huge\text{Good luck on your assignment \& enjoy your day!}


~\frak{Amphitrite1040:)}

3 0
2 years ago
Read 2 more answers
Help pls <br> Find the value of x
elena55 [62]

Answer:

x=61

Step-by-step explanation:

Because it is a 90 degree angle, you subtract the 29 from 90 and you get 61. You can also put in in this equation and arrive at the same conclusion.

90=X+29

3 0
2 years ago
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The zero of the function in A(x)=9x^2-25/3x+5 is <br><br> A. -5/3<br> B. 5/3<br> C. 5
trapecia [35]

it took me a while but the answer is 5/3

3 0
3 years ago
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One angle of an isosceles triangle measures 110°. Which other angles could be in that isosceles triangle? Choose all that apply.
BigorU [14]

Answer:

75 an 35 YEE YEE.

Step-by-step explanation:

im pretty sure

8 0
3 years ago
Write the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10).
Serjik [45]

Answer:

\displaystyle f(x)=x^2+2x+2

Step-by-step explanation:

<u>System Of Linear Equations </u>

In this problem, we'll need to solve a 3x3 system of linear equations because we have three unknowns and three conditions.

We are required to find the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10)

The general quadratic function can be written as

\displaystyle f(x)=ax^2+bx+c

We need to find the values of a,b, and c. Let's use the first condition, i.e. f(-1)=1

\displaystyle f(-1)=a(-1)^2+b(-1)+c

\displaystyle f(-1)=a-b+c

\displaystyle a-b+c=1.....[eq\ 1]

Now we use the second condition f(1)=5

\displaystyle f(1)=a(1)^2+b(1)+c

\displaystyle f(1)=a+b+c

\displaystyle a+b+c=5.......[eq\ 2]

Finally, we use the third condition f(2)=10

\displaystyle f(2)=a(2)^2+b(2)+c

\displaystyle f(2)=4a+2b+c

\displaystyle 4a+2b+c=10....[eq\ 3]

We put together eq 1, eq 2, and eq 3 to form the system

\displaystyle \left\{\begin{matrix}a-b+c=1\\ a+b+c=5\\ 4a+2b+c=10\end{matrix}\right.

Adding the first two equations we have

\displaystyle 2a+2c=6

\displaystyle a+c=3

And also

\displaystyle b=2

Using the above equation and the value of b in the third equation, we have

\displaystyle \left\{\begin{matrix}a+c=3\\ 4a+c=6\end{matrix}\right.

Subtracting the first equation from the second

\displaystyle 3a=3

\displaystyle a=1

And therefore

\displaystyle c=2

Now we have all the values, the quadratic function is

\displaystyle \boxed{f(x)=x^2+2x+2}

6 0
3 years ago
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