Help please!!!!

Mathematics

1 answer:

iris [78.8K]2 years ago

5 0

Answer:17.32

Step-by-step explanation:

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The line AB has midpoint (2,5).<br> A has coordinates (1, 2).<br> Find the coordinates of B.

Gekata [30.6K]

Answer:

$X_m = \frac{A_x +B_x}{2}= \frac{1+B_x}{2}= 2$

And we can solve for $B_x$ and we got:

$1+B_x = 4$

$B_x = 3$

$Y_m = \frac{A_y +B_y}{2}= \frac{2+B_y}{2}= 5$

And we can solve for $B_x$ and we got:

$2+B_y = 10$

$B_y = 8$

So then the coordinates for B are (3,8)

Step-by-step explanation:

For this case we know that the midpoint for the segment AB is (2,5)

And we know that the coordinates of A are (1,2)

We know that for a given segment the formulas in order to find the midpoint are given by:

$X_m = \frac{A_x +B_x}{2}= \frac{1+B_x}{2}= 2$

And we can solve for $B_x$ and we got:

$1+B_x = 4$

$B_x = 3$

$Y_m = \frac{A_y +B_y}{2}= \frac{2+B_y}{2}= 5$

And we can solve for $B_x$ and we got:

$2+B_y = 10$

$B_y = 8$

So then the coordinates for B are (3,8)

7 0

3 years ago

Sorry there is a few pics please help

Sever21 [200]

Answer:

Step-by-step explanation:

In the graph, there are only two values for a graph. In this case, those two values are crackers and calories.

7 0

3 years ago

Read 2 more answers

The line with equation x-3y-27=0 meets the parabola y²=4x at two points. Find their coordinates

lesantik [10]

$x-3y-27=0\\
y^2=4x\\\\
x-3y-27=0\\
x=\frac{y^2}{4}\\\\
\frac{y^2}{4}-3y-27=0\\
y^2-12y-108=0\\
y^2-12y+36-144=0\\
(y-6)^2=144\\
y-6=-12 \vee y-6=12\\
y=-6 \vee y=18\\\\
x=\frac{(-6)^2}{4} \vee x=\frac{18^2}{4}\\
x=\frac{36}{4} \vee x=\frac{324}{4}\\
x=9 \vee x=81\\\\
\boxed{(9,-6),(81,18)}
$