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Eddi Din [679]
3 years ago
6

Is there a mistake in this equation? if not please let me know!

Mathematics
2 answers:
Drupady [299]3 years ago
6 0

Answer:There is not any mistakes.

Step-by-step explanation:

Juli2301 [7.4K]3 years ago
5 0

Answer:

no mistakes

Step-by-step explanation:

4 * 3^x = 324

Divide each side by 4

4/4 * 3^x = 324/4

3^x = 81

Rewriting 81 as a power of 3

3^x = 3^4

Since the bases are the same, the powers are the same

x=4

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Solve the inequality <br> 21≥t+10
olchik [2.2K]

The answer is t ≤ 11.

  1. Subtract 10 from each side.
  • 21 - 10 ≥ t + 10 - 10
  • t ≤ 11

6 0
1 year ago
PLS HELP I ONLY NEED PART B
Mashcka [7]

Answer:

X= 2y - 3  

Kari makes X tryouts. She also makes 3 less than twice as many as Julie which would be X= 2y - 3

Julie makes y tryouts and twice would be 2y.

Step-by-step explanation: hope this helps!!! :)

7 0
2 years ago
Read 2 more answers
A) The failure rate in obtaining car license in every test held by Road Transport
sashaice [31]

Answer:

Step-by-step explanation:

5 0
2 years ago
Need help with stats!
KIM [24]

Answer:

A. a) 24

A. b) 4

B. a) 40320

B. b) 576

Step-by-step explanation:

General formula for Permutations:

P(n,r) = \frac{n!}{(n - r)!}

A. Concert seats:  2 couple --- total of 4 persons.

a) without restrictions

Since there are no restrictions, but that the order is important (John, Mary, Paul, Michelle isn't the  same as Michelle, Mary, Paul, John), it's a permutation calculation.

Then we calculate the permutations of 4, out of 4, so...

P(4,4) = \frac{4!}{(4 - 4)!} = 4! = 24

24 different ways for them to sit.

b) couples together

Now, we can see the problem as having 2 levels of permutations, first the couples, then inside the couples.

There are 2 ways for the first level or order... couples AB or BA, so 2 possibilities.

Inside each couple, man then woman (MW) or woman then man (WM), so 2 possibilities there too on 2nd level.

Overall 2 * 2 = 4 ways to sit by couple.

B) Single file

a) without restrictions

Again, order is important, so another permutation, not a combination.  And since we have no restriction, it can be any sequence.

We then have to calculate the number of permutations of 8 out of 8...

P(8,8) = \frac{8!}{(8 - 8)!} = 8! = 40320

There are 40,320 ways these 8 kids can pass the door.

b) girls first.

So, the four girls have to enter first.... and these four girls can be in any order.. how many permutations? P(4,4)... so 24 as calculated above.

For the four boys, how many permutations?  Yes, again P(4,4)... so 24 again.

Overall, we need to multiply the two... 24 x 24 = 576 ways if the girls enter first, followed by the boys.

8 0
3 years ago
Verify whether the indicated numbers are zeroes of their corresponding polynomials.
natita [175]

Answer:

  • No, incorrect

Step-by-step explanation:

<u>Given</u>

  • Q(s) = -4s^3 + 7s^2 - 24;
  • s = -4 and 1

<u>Verifying zeroes</u>

Q(-4) =

  • -4(-4)^3 + 7(-4)^2 - 24 =
  • 256 + 112 - 24 =
  • 344
  • Incorrect as 344 ≠ 0

Q(1) =

  • -4(1)^3 + 7(1)^2 - 24 =
  • -12 + 7 - 24 =
  • -29
  • Incorrect as -29 ≠ 0

8 0
3 years ago
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