∠13 = 70.5° [Vertically Opposite angles]
∠13+∠14=180° [Linear pair]
70.5°+∠14=180°
∠14=180-70.5
∠14=109.5
∠15=∠14=109.5 [Vertically opposite angles]
∠13=∠12= 70.5° [Co-interior angles]
∠12=∠10= 70.5° [Vertically Opposite angles]
∠14=∠11=109.5 [Co-interior angles]
∠9=∠11= 109.5 [Vertically opposite angles]
∠13=∠7= 70.5° [Alternate interior angles]
∠7=∠5=70.5° [Vertically Opposite angles]
∠7+∠8=180° [Linear Pair]
70.5+∠8=180
∠8=180-70.5
∠8=109.5°
∠8=∠6= 109.5° [Vertically Opposite angles]
∠6=∠3=109.5° [Co-interior angles]
∠7=∠2=70.5° [Co-exterior angles]
∠2=∠4= 70.5° [Vertically Opposite angles]
∠3=∠1= 109.5° [Vertically Opposite angles]

<h3>Measures of all angles in sequence⤵️</h3>
- ∠1= 109.5°
- ∠2= 70.5°
- ∠3= 109.5°
- ∠4= 70.5°
- ∠5= 70.5°
- ∠6= 109.5°
- ∠7= 70.5°
- ∠8= 109.5°
- ∠9= 109.5°
- ∠10= 109.5°
- ∠11= 70.5°
- ∠12= 109.5°
- ∠13= 70.5°
- ∠14= 109.5°
- ∠15= 109.5°
- ∠16= 70.5°
Answer:
The answer to your question is: letter B) 1/2
Step-by-step explanation:
Data
a = -2
b = 4
Equation
(1/2)a⁻⁴b²
Substitution
= (1/2)(-2)⁻⁴(4)²
= (1/2) (1 /2⁴)(4)²
= 1/2 (1/16) (16)
= 16 / 32
= 1 / 2
You can solve this problem and calculate the arc lenght, by applying the following formula:
s=θr
s: it is the arc lenght.
θ: it is the central angle (θ=2π/3).
r: it is the radius of the circle (r=10 inches).
When you substitute these values into the formula, you obtain the arc lenght (s):
s=θr
s=(2π/3)(10)
Then, you have that the value of the arc lenght is:
s=20.94 inches
Step-by-step explanation:
Given that,
A quadratic equation,
2x(x + 1.5) = -1
We need to solve the quadratic equation. Firstly we need to simplify the above equation to form it as
.
So,

Here, a = 2, b = 3 and c = 1
The roots of the given equation can be given by :

Putting all the values we get :

So, the roots of the given equation is -1/2 and -1.
Pick any two pairs of equations<span> from the system. Eliminate the same </span>variable<span> from each pair using the Addition/Subtraction method. Solve the system of the two new </span>equations<span> using the Addition/Subtraction method.</span>