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sergiy2304 [10]
3 years ago
6

In Neil's city, the temperature is 72.6 degrees and is rising 1.3 degrees each hour. In Sheppard's city, the temperature is 80.4

degrees and is dropping 1.82 degrees each hour. In how many hours will the temperature in Neil's city be no less than the temperature in Sheppard's city?
Mathematics
1 answer:
klio [65]3 years ago
8 0

Answer:

2.5 hours

Step-by-step explanation:

Given that :

Temperature in Neil's city :

72.6° and rising by 1.3° per hour

Temperature in Sheppard's city :

80.4° and dropping by 1.82° per hour

In how many hours will the temperature in Neil's city be no less than the temperature in Sheppard's city

Let number of hours = h

Hence, Neil city :

72.6 + 1.3h

Sheppard city:

80.4 - 1.82h

72.6 + 1.3h ≥ 80.4 - 1.82h

1.3h + 1.82h ≥ 80.4 - 72.6

3.12h ≥ 7.8

h ≥ 2.5

Two and half hours (2 hours 30 minutes)

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