Question

Find the distance CD rounded to the nearest tenth C=(10,-1) and D=(-6,3)

Answer 1

Answer:

CD = 16.5

Step-by-step explanation:

To find the distance between two points, use this formula: $L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }$

point C can be info set 1: (10, -1)    x₁ = 10   y₁ = -1

point D can be info set 2: (-6, 3)    x₂ = -6  y₂ = 3

Substitute the information into the formula

$L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }$

$CD = \sqrt{(-6 -10)^{2}+(3 -(-1))^{2} }$    Simplify inside each bracket

$CD = \sqrt{(-16)^{2}+(4)^{2} }$    Square the numbers

$CD = \sqrt{256+16 }$     Add inside the root

$CD = \sqrt{272}$    Enter into calculator

$CD = 16.5$  Rounded to the nearest tenth, the first decimal

The distance CD is 16.5.