When y is directly proportional to x,
y=kx (k is a constant)
when x=12, y=16
12k=16
k=4/3
hence, y=4/3x
To make y the subject, we must move everything to one side and y on the other.
Good day and I hoped that helped!
Answer:
the fuel efficiencies of the first car was 15 while the second car was 35
We use different models for different types of variation. For example, linear variation is associated with the formula y=ax, or the more familiar y=mx+b (the equation of a straight line). Cubic variation: y=a*x^3. In the present case we're discussing quadratic variation; perhaps that will ring a bell with you, reminding you that y=ax^2+bx+c is the general quadratic function.
Now in y our math problem, we're told that this is a case of quadratic variation. Use the model y=a*x^2. For example, we know that if x=2, y =32. Mind substituting those two values into y=a*x^2 and solving for y? Then you could re-write y=a*x^2 substituting this value for a. Then check thisd value by substituting x=3, y=72, and see whether the resulting equation is true or not. If it is, your a value is correct. But overall I got 16!
Answer:
37.375
Step-by-step explanation:
