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barxatty [35]
3 years ago
10

I need help with this please

Mathematics
2 answers:
Anit [1.1K]3 years ago
8 0

Hello.

We know that ΔSJL ≅ ΔDMT

∠S ≅ ∠D

∠J ≅ ∠M

∠L ≅ ∠T

                            __                                             __

So the segment  LS  corresponds to segment  TD

Natali [406]3 years ago
7 0

Answer:

the bottom answer choice : segment TD

Step-by-step explanation:

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Based on historical data, your manager believes that 40% of the company's orders come from first-time customers. A random sample
Vedmedyk [2.9K]

Answer:

P(0.26 \leq p \leq 0.43)=0.7204-0.0032=0.7172

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The population proportion have the following distribution

p \sim N(p=0.4,\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.4(1-0.4)}{91}}=0.0514)

And we can solve the problem using the z score on this case given by:

z=\frac{p_o -p}{\sqrt{\frac{p(1-p)}{n}}}

We are interested on this probability:

P(0.26 \leq p \leq 0.43)

And we can use the z score formula, and we got this:

P(\frac{0.26 -0.4}{\sqrt{\frac{0.4(1-0.4)}{91}}} \leq Z \leq \frac{0.43 -0.4}{\sqrt{\frac{0.4(1-0.4)}{91}}})

P(-2.726 \leq Z \leq 0.584)

And we can find this probability like this:

P(-2.726 \leq Z \leq 0.584)=P(Z

7 0
3 years ago
What is the square root of 25<br><br>a.4<br>b.21<br>c.10<br>d.1​
photoshop1234 [79]

the square root of 25 is 5

5x5=25

5 0
3 years ago
Read 2 more answers
Help please <br><br> hekfkdnr
mamaluj [8]

Answer:

first one is -16

second is -4

I'm what the third is

5 0
2 years ago
HELP due tomorrow morning at 7 30 help now please
olga55 [171]
1) 6/15 or 2/5
2) .4 or 40%

for the table its gonna be 14/32 or 7/16
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then 9/31 then 12/32 or 3/8 then 8/30 or 4/15 then 2/19 then 15/32
8 0
3 years ago
A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.
irakobra [83]

Answer:

The integral is equal to 5\sec^2(2x)+C for an arbitrary constant C.

Step-by-step explanation:

a) If u=\tan(2x) then du=2\sec^2(2x)dx so the integral becomes \int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C. (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case u=\sec(2x) hence du=2\tan(2x)\sec(2x)dx. We rewrite the integral as \int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C.

c) We use the trigonometric identity \tan(2x)^2+1=\sec(2x)^2 is part b). The value of the integral is 5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C. which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.  

3 0
3 years ago
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