1: w=3
2:w=-4
( 1): ''w2'' was replaced by ''w^2''
w^2+w-(12)=0
Given:
Teddy has two sisters. One of them is 3 years younger than Teddy, the other one is 7 years younger than her only brother.
To find:
The age of older sister at the time when the younger sister was born.
Solution:
Let the age of Teddy be x.
One sister is 3 years younger than Teddy.
Age of one sister = x-3 years
The other one is 7 years younger than her only brother. It means other sister is 7 years younger than Teddy.
Age of other sister = x-7 years
Clearly (x-3) > (x-7). So, difference between the ages of sisters is



Therefore, the age of older sister is 4 years when the younger sister was born.
Answer:
Option D
Step-by-step explanation:
(8x^2-9y^2-4x) +(x^2-3y^2-7x)
8x^2+x^2-9y^2-3y^2-4x-7x
9x^2-12y^2-11x
The expression isn’t there I can’t answer it.