The quadrilateral ABCD is a rhombus with diagonals AC = 12 ft and BD = 4 ft. The points M and N divide diagonal AC on three equa
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Answer:
Step-by-step explanation:
Hello,
<u>I assume that you want to solve this system of two equations</u>
(1) 5x - y = -7
(2) 4x + 2y = -14
We will multiply (1) by 2 and add to (2) so that we can eliminate the terms in y
2*(1)+(2) gives
10x - 2y + 4x + 2y = -7*2 -14 = -14 - 14 = -28
<=>
14x = - 28 we can divide by 14 both parts
x = -28/14 = -2
and then we replace x in (1)
5*(-2)-y=-7
-10-y=-7 add 7
-10-y+7=0
-3-y=0 add y
-3 = y
which is equivalent to y = -3
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