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Finger [1]
4 years ago
6

The quadrilateral ABCD is a rhombus with diagonals AC = 12 ft and BD = 4 ft. The points M and N divide diagonal AC on three equa

l parts. Prove that BMDN is a square and find its area.
Mathematics
1 answer:
victus00 [196]4 years ago
8 0

Answer:

area of BMDN 8 ft²

Step-by-step explanation:

In BMDN the diagonals are BD and MN.

MN is 12/3 = 4 ft long, and BD = 4 ft.

A rhombus with equal diagonals is a square, so BMDN is a square.

In the right triangle BDN, the diagonal BD is the hypotenuse, then:

DN² + NB² = BD²

but DN = NB, then:

2*DN² = 16 ft²

DN² = 8 ft²

The area of BMDN is computed as one of its sides squared. Then, DN² is its area

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In the diagram, the radius is 7 and tangent AB has length of 24. Determine the length of OA rounded to the nearest whole number
katen-ka-za [31]

Given the radius r and the tangent line AB, the length of the line OA is 24 units

<h3>How to determine the length OA?</h3>

The radius r and the tangent line AB meet at a right angle.

By Pythagoras theorem, we have:

AB² = OA² + r²

So, we have:

24² = OA² + 7²

Rewrite as:

OA² = 24² - 7²

Evaluate

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2 years ago
How do you work out this problem, step by step please I am so lost. Year Average Household Income (before taxes) Food Housing Tr
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Step-by-step explanation:

In the Year 2000

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Therefore:

(a)Percentage of the average household income in 2000 was spent on food

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3 0
3 years ago
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Calculate the partial sum S for the sequence 243,81,27,....
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Answer:363


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