Une échelle est posée contre un mur et une caisse cubique de 1m de côté La distance entre le bas de l'échelle et la caisse est d
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Answer:
Step-by-step explanation:
I'm assuming you are solving this system for x, y, and z. Do it this way:
Combine the first 2 equations and the second 2 equations and eliminate the y's. The first 2 equations:
x + y + z = 3
x - y + z = 2
which solves to
2x + 2z = 5
The second 2 equations:
x - y + z = 2
x + y - z = 1
which solves to
2x = 3 so
x = 3/2 or 1.5
Now sub that x value into the bold equation above to get:
2(1.5) + 2z = 5 and
3 + 2z = 5 and
2z = 2 so
z = 1
Now we plug back in to solve for y:
1.5 + y + 1 = 3 and
2.5 + y = 3 so
y = .5
The solution set then is (1.5, .5, 1) or in fraction form: