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Softa [21]
3 years ago
6

A car was originally purchased in January 2010 for 27000 dollars. The car depreciates at a rate of 18% every year.

Mathematics
1 answer:
Maksim231197 [3]3 years ago
5 0

Answer:

Number of year(n) = 3.4 year (Approx)

Step-by-step explanation:

Given:

Purchase value of car = $27,000

Depreciation rate per year (d) = 18% = 0.18

Future price = half of its original value = $27,000 / 2 = $13,500

Find:

Number of year(n) = ?

Computation:

Future price  =Purchase value(1-d)^n\\\\13,500=27,000(1-0.18)^n\\\\0.5=(0.82)^n\\\\n=3.444(Approx)

Number of year(n) = 3.4 year (Approx)

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The amount in kilograms, a, of a radioactive element that remains after t hours can be modeled by the equation a= 0.65(0.92)to t
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Answer:

The rate of decrease is 8%

Step-by-step explanation:

we know that

The general equation for the radioactive decay can be written as:

a=a_0(1-r)^t

where

a is the amount in kilograms after time t.

a_0 is the original amount of the substance or y-intercept of the function

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t is the time

In this problem we have

a=0.65(0.92)^t

so

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If g(x) = 2x2 + 6x + 5, use synthetic division to find g(-5).
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<h3>Answer:  25</h3>

=================================================

Explanation:

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