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kramer
2 years ago
7

|x-5|=3 Whats x? please help?

Mathematics
2 answers:
Irina-Kira [14]2 years ago
4 0
Answer:
x = 8
x = 2

Step-by-step explanation:

Separate into two equations:

x - 5 = 3
x - 5 = -3

Now solve:
x - 5 = 3
+ 5 +5
x = 8

x - 5 = -3
+ 5 + 5
x = 2



Hope this helps!
finlep [7]2 years ago
3 0

Answer:

x = 8 or x = 2

Step-by-step explanation:

We know x - 5 = 3 or x - 5 = -3.

<u>Possibility 1:</u>

Step 1: Add 5 to both sides.

  • x-5+5=3+5
  • x=8

<u>Possibility 2:</u>

Step 1: Add 5 to both sides.

  • x-5+5=-3+5
  • x=2

Step 2: Check if both solutions apply to original equation.

  • |8-5|=3
  • |3|=3
  • 3=3
  • |2-5|=3
  • |-3|=3
  • 3=3

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Steve just signed a lease to rent a new apartment. His monthly rent will be $800.00, and he will have to pay a one-time nonrefun
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Answer:

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Step-by-step explanation:

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For a test of population proportion H0: p = 0.50, the z test statistic equals 1.05. Use 3 decimal places. (a) What is the p-valu
sergiy2304 [10]

Answer:

(a) The <em>p</em>-value of the test statistic is 0.147.

(b) The <em>p</em>-value of the test statistic is 0.294.

(c) The <em>p</em>-value of the test statistic is 0.8531.

(d) None of the <em>p</em>-values give strong evidence against the null hypothesis.

Step-by-step explanation:

The <em>p</em>-value is well defined as the probability,[under the null hypothesis (H₀)], of attaining a result equivalent to or greater than what was the truly observed value of the test statistic.

We reject a hypothesis if the p-value of a statistic is lower than the level of significance <em>α</em>.

The null hypothesis for the test of population proportion is defined as:

<em>H₀</em>: <em>p</em> = 0.50

The value of <em>z</em>-test statistic is,

<em>z</em> = 1.05

(a)

The alternate hypothesis is defined as:

<em>Hₐ</em>: <em>p</em> > 0.50

Compute the <em>p</em>-value of the test statistic as follows:

p-value=P(Z>1.05)\\=1-P(Z

*Use a <em>z</em>-table for the probability value.

Thus, the <em>p</em>-value of the test statistic is 0.147.

(b)

The alternate hypothesis is defined as:

<em>Hₐ</em>: <em>p</em> ≠ 0.50

Compute the <em>p</em>-value of the test statistic as follows:

p-value=2\times P(Z>1.05)\\=2\times 0.1469\\=0.2938\\\approx 0.294

*Use a <em>z</em>-table for the probability value.

Thus, the <em>p</em>-value of the test statistic is 0.294.

(c)

The alternate hypothesis is defined as:

<em>Hₐ</em>: <em>p</em> < 0.50

Compute the <em>p</em>-value of the test statistic as follows:

p-value= P(Z1.05)=1- 0.1469\\=0.8531

*Use a <em>z</em>-table for the probability value.

Thus, the <em>p</em>-value of the test statistic is 0.8531.

(d)

The decision rule of the test is:

If the <em>p</em>-value of the test is less than the significance level <em>α</em>, then the null hypothesis is rejected at <em>α</em>% level of significance.

And if the <em>p</em>-value of the test is more than the significance level <em>α</em>, then the null hypothesis is failed to be rejected.

The most commonly used level of significance are:

<em>α</em> = 0.01, 0.05 and 0.10

The <em>p</em>-value for all the three alternate hypothesis are:

<em>p-</em>values = 0.147, 0.294 and 0.8531.

All the <em>p</em>-values are quite large compared to the <em>α</em> values.

Thus, none of the <em>p</em>-values give strong evidence against the null hypothesis.

The null hypothesis was failed to be rejected.

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